2013-02-26 89 views
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感謝@Tim WIlliams我有以下生成插入語句的代碼。但是,當我添加下面的子項來調用它來傳輸工作簿時,它仍然只拾取活動工作表。我究竟做錯了什麼?遍歷工作表

Sub WorksheetLoop() 

    Dim WS_Count As Integer 
    Dim I As Integer 
    Dim current As Worksheet 
    ' Set WS_Count equal to the number of worksheets in the active 
    ' workbook. 
    WS_Count = ActiveWorkbook.Worksheets.Count 

    ' Begin the loop. 
    For Each current In ActiveWorkbook.Worksheets 


     Call DoSQL 

     'MsgBox ActiveWorkbook.Worksheets(I).Name 

    Next 

    End Sub 

    Sub DoSQL() 
    myfile = "test.txt" 
    fnum = FreeFile() 
    Open myfile For Output As fnum 

    Const SQL = "insert into <tbl>(<cols>) values (<vals>)" 
    Dim dictSQL As Object, rw1 As Range, r As Long, rowSQL 
    Dim sht As Worksheet, k, c As Range 
    Dim cols, vals 

    'Set sht = ActiveSheet 
    Set rw1 = sht.Range(sht.Cells(1, 1), sht.Cells(1, Columns.Count).End(xlToLeft)) 

    Set dictSQL = tableDict(rw1) 

    r = 2 

    Do While sht.Cells(r, 1).Value <> "" 

     For Each k In dictSQL 
      rowSQL = Replace(SQL, "<tbl>", k) 
      cols = "" 
      vals = "" 

      For Each c In dictSQL(k).Cells 
       cols = cols & IIf(Len(cols) > 0, ",", "") & Split(c.Value, ".")(1) 
       vals = vals & IIf(Len(vals) > 0, ",", "") & _ 
          "'" & Trim(sht.Cells(r, c.Column).Value) & "'" 
      Next c 

      rowSQL = Replace(rowSQL, "<cols>", cols) 
      rowSQL = Replace(rowSQL, "<vals>", vals) 
      Debug.Print rowSQL 
      Print #fnum, rowSQL 
     Next k 

     r = r + 1 
    Loop 
    Close #fnum 

    End Sub 

    Function tableDict(rw As Range) 
    Dim rv As Object, tbl 
    Set rv = CreateObject("scripting.dictionary") 
    Dim c As Range 
    For Each c In rw.Cells 
     If Len(c.Value) > 0 And InStr(c.Value, ".") > 0 Then 
      tbl = Split(c.Value, ".")(0) 'table name 
      If rv.exists(tbl) Then 
       Set rv(tbl) = Application.Union(c, rv(tbl)) 
      Else 
       rv.Add tbl, c 
      End If 
     End If 
    Next c 
    Set tableDict = rv 
    End Function 
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我已經編輯了我的原始答案以添加循環... – 2013-02-26 18:57:33

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我解決了這個問題。我錯過了 For Each current In Application.Worksheets current.Activate – 2013-02-26 18:59:53

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@TimWilliams再次感謝你 – 2013-02-26 19:01:05

回答

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您絕對不會更改for語句中的工作表,因此DoSQL子句總是從同一工作表中抽取數據。您可能需要選擇循環中的當前工作表,或將當前數據傳遞給DoSQL子項以供使用。

這應該可以解決這個問題:

For Each current In ActiveWorkbook.Worksheets 
     Current.Select 
     Call DoSQL 
     'MsgBox ActiveWorkbook.Worksheets(I).Name 
    Next 
1

作爲替代Ripster's answer,你可以在current片傳遞給DoSQL子...

For Each current In ActiveWorkbook.Worksheets 
    DoSQL(current) 
Next 

,改變你的子匹配。 ..

Sub DoSQL(sht As Worksheet) 
    myfile = "test.txt" 
    fnum = FreeFile() 
    Open myfile For Output As fnum 

    Const SQL = "insert into <tbl>(<cols>) values (<vals>)" 
    Dim dictSQL As Object, rw1 As Range, r As Long, rowSQL 
    Dim k, c As Range 
    Dim cols, vals 

    'Your code continues... 

附註:一般來說,使用ActiveSheet/ActiveWorkbook並不是一個好主意,因爲如果您的代碼在進程中激活不同的對象時,它可能會被混淆。爲了避免這個問題,你應該明確地設置每個工作表爲一個對象(不使用ActiveSheet!)。 'ThisWorkbook'將確保代碼僅在代碼被調用的工作簿上運行,這是通過ActiveWorkbook正確方向的一步。

另一方面說明:你還應該養成明確聲明變量的習慣。如果未指定數據類型,則使用默認的Variant類型,這將佔用比簡單類型(Integer等)更多的內存。此外,在一條線上調光多個變量是允許的,但每個變量都必須符合型號規格。

換句話說,以下(來自您的代碼)會產生2個變量,其中一個(c)類型爲Range,另一個(k)爲變體。

Dim k, c As Range 

最後(然後我就下車,我的香皂盒):它是使用Option Explicit(只需添加到您的所有模塊的頂部)執行的變量聲明一個非常好的主意。如果不這樣做,可能會導致更嚴格的時間追蹤某些錯誤,而這些錯誤在運行時纔會被捕獲。

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+1不選擇,不使用activesheet/activeworkbook,並解釋k是一個變體。 – 2013-02-26 20:21:42