PHP陣列元件，和變量作爲索引

Question

我喜歡這些多個記錄：

2011-01-01, a, 1 
2011-01-01, c, 5 
2011-01-01, d, 3 
2011-01-02, a, ... 

的第一個值的日期，第二個是一個字符串（可以是a或b或c或d ），第三個是一個數字。

如何添加的所有記錄到PHP中的數組，數組的結構是這樣的：

array('2011-01-01' => array('a' => '1','b' => '0','c' => '5','d' => '3'), '2011-01-02' => ... ,) 

以便日期變量是一個指標，關鍵是四元素的數組，每個元素是相應的記錄號碼（第三個值）？

Answer 1

這個怎麼樣（假設你的輸入數據的格式） ：

$input = array(
    array('2011-01-01', 'a', '1'), 
    array('2011-01-01', 'c', '5'), 
    array('2011-01-01', 'd', '3'), 
    array('2012-01-01', 'a', '1') 
); 

// used to populate the default strings (a b c d) 
$strings = range('a', 'd'); 
$stringDefaults = array_combine($strings, array_fill(0, count($strings), '0')); 

$output = array(); 

foreach ($input as $row) { 
    list ($date, $string, $number) = $row; 

    if (!isset($output[$date])) { 
     $output[$date] = $stringDefaults; 
    } 

    $output[$date][$string] = $number; 
} 

echo json_encode($output); 

Answer 2

假設這是一個很大的字符串，請將它拆分爲行，然後再分隔逗號。對於每一行，測試日期是否已經存在的一個關鍵，如果確實如此，添加到它，否則，創建它：

$string = "2011-01-01, a, 1 
2011-01-01, c, 5 
2011-01-01, d, 3 
2011-01-02, a, 1"; 

// Array to hold it all... 
$array = array(); 
$lines = explode("\n", $string); 
foreach ($lines as $line) { 
    // Explode the line on the comma into 3 variables 
    list($date, $key, $num) = explode(",", $line); 
    $date = trim($date); 
    $key = trim($key); 
    $num = intval($num); 

    // Create an array key for the current $date if it doesn't exist 
    // as a new array 
    if (!isset($array[$date])) $array[$date] = array(); 

    // And assign the number with the corresponding letter key to the array 
    // for this date. 
    $array[$date][$key] = $num; 
} 

Answer 3

$records = array(
    0 => array('2011-01-01', 'a', '1'), 
    1 => array('2011-01-01', 'c', '5'), 
    2 => array('2011-01-01', 'd', '3'), 
    3 => array('2012-01-01', 'a', '1') 
); 

$tmp_arr = array(); 
$tmp_dates = array(); 
$tmp_str = ''; 

foreach ($records as $record) { 
    $tmp_arr[$record[0]][$record[1]] = $record[2]; 
} 

foreach ($tmp_arr as $date => $record) { 
    $tmp_params = array(); 
    foreach ($record as $key => $val) { 
     $tmp_params[] = $key . ':' . $val; 
    } 
    $tmp_dates[] = $date . ':' . '{' . implode(',', $tmp_params) . '}'; 
} 

$tmp_str = '{' . implode(',', $tmp_dates) . '}'; 

echo $tmp_str; // {2011-01-01:{a:1,c:5,d:3},2012-01-01:{a:1}} 

Answer 4

前提是你的數據在一個文本文件（.txt）：

$records = file_get_contents("filename.txt"); 

// $records will be equal to the following: (on windows, it would be \r\n instead of just \n) 
// $records = "2011-01-01, a, 1\n2011-01-01, c, 5\n2011-01-01, d, 3\n 2011-01-02, d, 3"; 

$records = explode("\n", $records); 

$output = array(); 

for ($i = 0; $i < count($records); $i++) { 

    $rec = explode(",", $records[$i]); 
    $key = $rec[0]; 

    if ($output[$key] == null) 
     $output[$key] = array(); 

    if (!array_key_exists("a", $output[$key])) 
     $output[$key]["a"] = 0; 

    if (!array_key_exists("b", $output[$key])) 
     $output[$key]["b"] = 0; 

    if (!array_key_exists("c", $output[$key])) 
     $output[$key]["c"] = 0; 

    if (!array_key_exists("d", $output[$key])) 
     $output[$key]["d"] = 0; 

    $elem = trim($rec[1]); 
    $value = trim($rec[2]); 
    $output[$key][$elem] = intval($value); 

} 

var_dump($output); 

Answer 5

好吧，這裏就是你要做的。

$records = array(
    0 => array('2011-01-01', 'a', '1'), 
    1 => array('2011-01-01', 'c', '5'), 
    2 => array('2011-01-01', 'd', '3'), 
    3 => array('2012-01-01', 'a', '1') 
); 

$dateArray = array(); 
$baseArray = array('a' => '0','b' => '0','c' => '0','d' = '0'); 

foreach($records as $record) 
{ 
    $dateArray[$record[0]][$record[1]] = $record[2]; //You could actually do this while pulling in the info from the DB 
} 

foreach($dateArray as $date => $array) 
{ 
    $missingArray = array_diff_key($array,$baseArray); //Determine what keys are missing using the base array, get keys and default values 
    $dateArray[$date] = array_merge($array,$missingArray); //Merge the missing parts with the current array 
} 

請注意，從其他帖子複製時間的零件。