ASP.NET/C#：從天

的列表基於最近的未來日期，我想從天列表獲取基於最近的：ASP.NET/C#：從天

方案1：

Date: July 22, 2013 (Monday) 
Possible days: "Tuesday", "Wednesday", "Friday" (string values) 
Answer: July 23, 2013 (Tuesday)

方案2：

Date: July 23, 2013 (Tuesday) 
Possible days: "Tuesday", "Wednesday", "Thursday", "Saturday" 
Answer: July 24, 2013 (Wednesday)

方案3：

Date: July 24, 2013 (Wednesday) 
Possible days: "Monday", "Tuesday" 
Answer: July 29, 2013 (Monday)

有什麼建議嗎？

來源

2013-07-22 abramlimpin

最近即將推出的唯一的或過去的一天好？ – Ehsan

@EhsanUllah只是未來的日子。（更新了詳細信息） – abramlimpin

請檢查第一個場景。 22是星期一，21是星期二，你是怎麼得到的？ – Uriil

DateTime date = DateTime.Parse("July 22, 2013"); 
     DayOfWeek dateDay = date.DayOfWeek; 
     DayOfWeek[] possibleDays = { DayOfWeek.Tuesday,DayOfWeek.Wednesday,DayOfWeek.Friday }; 
     int addToBestAnswer = 7; 
     foreach (var checkDay in possibleDays) 
     { 
      if (checkDay-dateDay<addToBestAnswer) 
      { 
       addToBestAnswer = checkDay - dateDay; 
      } 
     } 
     DateTime Answer = date.AddDays(addToBestAnswer);

編輯：僅用於字符串輸入：

DateTime date = DateTime.Parse("July 22, 2013"); 
     string[] possibleDays={ "Tuesday","Wednesday","Friday" }; 

     List<int> pDays = new List<int>(); 
     foreach (var inputDay in possibleDays) 
     { 
      pDays.Add(int.Parse(inputDay.Replace("Sunday", "0").Replace("Monday", "1").Replace("Tuesday", "2").Replace("Wednesday", "3").Replace("Thursday", "4").Replace("Friday", "5").Replace("Saturday", "6"))); 
     } 
     int dateDay = (int)date.DayOfWeek; 

     int addToBestAnswer = 7; 
     foreach (var checkDay in pDays) 
     { 
      int difference = checkDay - dateDay; 
      if (difference<0) 
      { 
       difference = 7 + difference; 
      } 
      if (difference<addToBestAnswer&&difference!=0) 
      { 
       addToBestAnswer = difference; 
      } 
     } 
     DateTime Answer = date.AddDays(addToBestAnswer); 
     // Answer.ToShortDateString()+" ("+Answer.DayOfWeek.ToString()+")";

來源

2013-07-22 14:11:27 MMMagic

可能的日子被列爲字符串值。 – abramlimpin

爲此添加了解決方案 – MMMagic

非常感謝！像魅力一樣工作。 – abramlimpin

是否這樣？

public DateTime GetNextPossibleDay(DateTime DT, DayOfWeek[] PossibleDays) 
    { 
     if (PossibleDays.Length == 0) 
      throw new Exception("No possible day."); 

     do 
     { 
      DT = DT.AddDays(1); 
     } 
     while (!PossibleDays.Contains(DT.DayOfWeek)); 

     return DT; 
    }

來源

2013-07-22 13:49:36 TTT

您可以檢查每個日期在列表中，除非你正確的，是這樣的：

var days = new List<string> {"Tuesday", "Monday"}; 
    var startDate = new DateTime(2013, 7, 24).AddDays(1); 
    while (!days.Contains(startDate.DayOfWeek.ToString("G"))) 
    { 
     startDate = startDate.AddDays(1); 
    } 
    Console.WriteLine(startDate);

來源

2013-07-22 13:50:48 Uriil

這應該工作：

var date = new DateTime(2013, 07, 24); 
var posibleDays = new[]{DayOfWeek.Tuesday,DayOfWeek.Wednesday,DayOfWeek.Friday}; 

var nearestDay = posibleDays.Select(dow => new { 
    DayOfWeek = dow, 
    Diff = (7 + (dow - date.DayOfWeek)) % 7 
}) 
.Where(x => x.Diff >= 1) 
.OrderBy(x => x.Diff) 
.FirstOrDefault();

靈感來自question of myself一段時間前。如果DayOfWeek的值早於另一個值，它假定在下一週有一天。

這裏跟你的樣品數據演示：http://ideone.com/VzZnzx

來源

2013-07-22 13:52:08

測試。此代碼的工作

List<DayOfWeek> days = new List<DayOfWeek>() { DayOfWeek.Tuesday, DayOfWeek.Wednesday }; 
     DateTime sourceDate = DateTime.Now; 
     DayOfWeek currentDay = sourceDate.DayOfWeek; 

     int? smallestValue = null; 

     foreach (DayOfWeek d in days) 
     { 
      int currentValue = (int)d - (int)currentDay; 
      if (!smallestValue.HasValue) 
       smallestValue = currentValue; 

      if(smallestValue > currentValue) 
       smallestValue = currentValue; 

     } 

     DateTime nearestDate = sourceDate.AddDays(smallestValue.Value);

來源

2013-07-22 13:54:37 Ehsan

抱歉，我沒有收到您的問題 – Ehsan

它仍然建議同一天。 – abramlimpin

你能告訴我你的代碼嗎？ – Ehsan

不是花哨LINQ的，但這個工程=）

public static DateTime NearestDate(DateTime baseDateTime, List<string> acceptedDays) 
    { 
     DateTime result = new DateTime(baseDateTime.Year, baseDateTime.Month, baseDateTime.Day); 

     List<DayOfWeek> acceptedDoW = new List<DayOfWeek>(); 
     acceptedDays.ForEach(x => acceptedDoW.Add((DayOfWeek)Enum.Parse(typeof(DayOfWeek), x, true))); 

     DayOfWeek currentDay = baseDateTime.DayOfWeek; 

     int closestDay = int.MaxValue; 

     acceptedDoW.ForEach(x => 
      { 
       int currentSpan = (int)x; 

       if (x < currentDay) 
        currentSpan += 7; 

       currentSpan = currentSpan - (int)currentDay; 

       if (currentSpan < closestDay) 
        closestDay = currentSpan; 
      }); 

     return result.AddDays(closestDay); 
    }

來源

2013-07-22 13:58:30

ASP.NET/C#：從天

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