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夥計們我有這個查詢,得到一個關鍵字,並在數據庫中搜索一系列文章,根據關鍵字查詢結果顯示,然後我需要根據我得到的ID和顯示它獲取有關這些文章的信息。查詢沒有完成,有人可以幫我清理下一個代碼並改進它嗎?MySQL:PHP在查詢的同時又用查詢,如何提高?
謝謝
$cleanKeyword = str_replace("+", " ", $keyword);
$i = mysql_query("SELECT IdNorma FROM $cpalabras WHERE Descripcion = '$cleanKeyword'");
while($materia = mysql_fetch_array($i)){
// storing idNorma into a variable
$IdNorma = $materia['IdNorma'];
$SQL = "SELECT n.*, j.Descripcion as jurisdiccion,
t.Descripcion as tipo,
date_format(n.FechaDesde,'%d') as dia,
date_format(n.FechaDesde,'%m') as mes,
date_format(n.FechaDesde,'%Y') as anio
FROM c_normas as n, c_jurisdiccion as j, c_tiponorma as t, c_materia as m
WHERE 1=1 ";
$SQL .= "AND n.IdNorma = '$IdNorma' ";
$SQL .= "ORDER BY Fechadesde DESC LIMIT 300";
var_dump($SQL);
$a = mysql_query($SQL);
if(mysql_num_rows($a) > 0) {
while($row = mysql_fetch_array($a)){ ?>
<tr style="display:inline-block;width:100%;border-bottom:1px solid #E3E6EB;padding:4px 0;font-size: 10px;" class="listaEventoUnicoTr" id="quickSearchTr">
<td width="120" align="left" id="searchable"><strong><?php echo fromDB($row['tipo']); ?></strong></td>
<td width="90" align="left"><a href="http://www.ips.com.ar/normmunipC/IPS_Municipal_files/files/<?php echo fromDB($row['Archivo']); ?>" target="_blank"><?php echo fromDB($row['Numero']); ?></a></td>
<td width="90" align="left" id="searchable"><?php echo fromDB($row['dia'])."-".fromDB($row['mes'])."-".fromDB($row['anio']); ?></td>
<td width="255" align="left" style="padding-top:4px;padding-bottom:4px;" id="searchable"><?php echo fromDB($row['Descripcion']); ?></td>
</tr>
<?php } //while
} else { //if ?>
<tr style="display:inline-block;width:100%;border-bottom:1px solid #E3E6EB;padding:4px 0;font-size: 10px;" class="listaEventoUnicoTr" id="quickSearchTr">
<td width="500" align="center" colspan="4"> No hay resultados.</td>
</tr>
<?php } // else
}// /while ids
謝謝你們!
開始學習如何使用JOIN的SQL查詢 – 2011-03-03 13:21:48