的JTable與JPopupMenu的

Question

如何防止觸發和顯示JPopupMenu僅是Mouse Cursor在選定JTable'Row

我的問題：如果有另一種方式爲getBounds從選定的行和確定/比較，與Mouse位置...

我簡單SSCCE證明只是未想相反的狀態，任何行可以選擇JPopupMenu從整個JTable

import java.awt.event.*; 
import javax.swing.*; 
import javax.swing.table.*; 

public class TableCheckBox extends JFrame { 

    private static final long serialVersionUID = 1L; 
    private JTable table; 

    public TableCheckBox() { 
     Object[] columnNames = {"Type", "Company", "Shares", "Price", "Boolean"}; 
     Object[][] data = { 
      {"Buy", "IBM", new Integer(1000), new Double(80.50), false}, 
      {"Sell", "MicroSoft", new Integer(2000), new Double(6.25), true}, 
      {"Sell", "Apple", new Integer(3000), new Double(7.35), true}, 
      {"Buy", "Nortel", new Integer(4000), new Double(20.00), false} 
     }; 
     DefaultTableModel model = new DefaultTableModel(data, columnNames); 
     table = new JTable(model) { 

      private static final long serialVersionUID = 1L; 

      @Override 
      public Class getColumnClass(int column) { 
       return getValueAt(0, column).getClass(); 
      } 
     }; 
     table.setPreferredScrollableViewportSize(table.getPreferredSize()); 
     JScrollPane scrollPane = new JScrollPane(table); 
     add(scrollPane); 
     createPopupMenu(); 
    } 

    private void createPopupMenu() { 
     JPopupMenu popup = new JPopupMenu(); 
     JMenuItem myMenuItem1 = new JMenuItem("cccccccccccccccccccccc"); 
     JMenuItem myMenuItem2 = new JMenuItem("bbbbbbbbbbbbbbbbbbbbbb"); 
     popup.add(myMenuItem1); 
     popup.add(myMenuItem2); 
     MouseListener popupListener = new PopupListener(popup); 
     table.addMouseListener(popupListener); 
    } 

    private class PopupListener extends MouseAdapter { 

     private JPopupMenu popup; 

     PopupListener(JPopupMenu popupMenu) { 
      popup = popupMenu; 
     } 

     @Override 
     public void mousePressed(MouseEvent e) { 
      maybeShowPopup(e); 
     } 

     @Override 
     public void mouseReleased(MouseEvent e) { 
      if (table.getSelectedRow() != -1) { 
       maybeShowPopup(e); 
      } 
     } 

     private void maybeShowPopup(MouseEvent e) { 
      if (e.isPopupTrigger()) { 
       popup.show(e.getComponent(), e.getX(), e.getY()); 
      } 
     } 
    } 

    public static void main(String[] args) { 
     SwingUtilities.invokeLater(new Runnable() { 

      @Override 
      public void run() { 
       TableCheckBox frame = new TableCheckBox(); 
       frame.setDefaultCloseOperation(EXIT_ON_CLOSE); 
       frame.pack(); 
       frame.setLocation(150, 150); 
       frame.setVisible(true); 
      } 
     }); 
    } 
} 

觸發

Answer 1

這是一個有趣的問題，因爲它突出在JComponent上缺少api :-)

衆所周知，推薦的popupMenus註冊方法是使用componentPopupMenu屬性。相關API是

void setComponentPopupMenu(JPopupMenu); 
JPopupMenu getComponentPopupMenu(); 
Point getPopupLocation(MouseEvent); 

缺什麼（和實際需要爲這個要求）是

JPopupMenu getComponentPopupMenu(MouseEvent); 

這種缺乏是更加惱人，因爲getPopupLocation被稱爲（由AWTEventHelper深的LAF） getComponentPopup（）。因此，存儲最後一個可能觸發彈出窗口的鼠標事件，然後決定哪個/如果返回彈出窗口是沒有餘地的。並且返回空位置只會導致在鼠標位置顯示它

唯一（髒）黑客（圍繞我完全不願意讓我的手弄髒MouseListener ;-)是重寫getComponentPopup並決定是否或者不將其基於當前鼠標位置

table = new JTable(model) { 

     /** 
     * @inherited <p> 
     */ 
     @Override 
     public JPopupMenu getComponentPopupMenu() { 
      Point p = getMousePosition(); 
      // mouse over table and valid row 
      if (p != null && rowAtPoint(p) >= 0) { 
       // condition for showing popup triggered by mouse 
       if (isRowSelected(rowAtPoint(p))) { 
        return super.getComponentPopupMenu(); 
       } else { 
        return null; 
       } 
      } 
      return super.getComponentPopupMenu(); 
     } 

    }; 

副作用是彈出式的表現不被鍵盤，只要鼠標在桌子上方的任何位置觸發，這可能是或不是一個問題返回。

Answer 2

您是否在尋找類似的東西？

要顯示彈出在選定行（S）僅

private void maybeShowPopup(MouseEvent e) { 
    if (e.isPopupTrigger()) { 

     // get row that pointer is over 
     int row = table.rowAtPoint(e.getPoint()); 

     // if pointer is over a selected row, show popup 
     if (table.isRowSelected(row)) { 
      popup.show(e.getComponent(), e.getX(), e.getY()); 
     } 
    } 
    } 

或者反過來，以防止彈出窗口只顯示在選定行：

private void maybeShowPopup(MouseEvent e) { 
    if (e.isPopupTrigger()) { 
     int row = table.rowAtPoint(e.getPoint()); 
     int[] selectedRows = table.getSelectedRows(); 

     if (!table.isRowSelected(row)) { 
      popup.show(e.getComponent(), e.getX(), e.getY()); 
     } 
    }