詹金斯工作流程存放扁平化文件夾

是否有可能將一組隱藏的工件作爲扁平目錄進行拆分，就像您可以使用jenkins存檔一樣？詹金斯工作流程存放扁平化文件夾

我希望它有3個文件夾隱藏，只有一個與3的所有內容不沾，但我目前無法完成。

這裏是我的嘗試：

echo("Workflow Starting..."); 
node { 
    def imageNames = ["connector","registryloader","salepersistence","settlement","standalone","trackingloader"] 
    stage 'Building 
     checkout([$class: 'SubversionSCM', additionalCredentials: [], excludedCommitMessages: '', excludedRegions: '', excludedRevprop: '', excludedUsers: '', filterChangelog: false, ignoreDirPropChanges: false, includedRegions: '', locations: [[credentialsId: '36c9ca9f-de25-4022-b9eb-70ada8e793b8', depthOption: 'infinity', ignoreExternalsOption: true, local: '.', remote: 'http://10.64.111.28/svn/SampleProject/skl-br']], workspaceUpdater: [$class: 'UpdateUpdater']]) 
     withEnv(["PATH+MAVEN=${tool 'M3'}/bin"]) { 
     bat "mvn clean install assembly:assembly versions:resolve-ranges -Dmaven.test.skip=false -DskipTests" 
     } 
     echo("Archiving") 
     archive '**/target/*.tar.gz, conf/desenv/**/*' 
     for(int i = 0; i < imageNames.size(); i++){ 
     String imageName = imageNames[i] 
     echo("Stashing ${imageName}") 
     stash excludes: '', includes: '**/sklbr-1.0.0-standalone.tar.gz, **/'+imageName+'/*, **/commonConfigs/*, **/scripts/*', name: ''+imageName+'' 
     } 

    stage 'Creating Container' 

     docker.withServer('tcp://localhost:2375') 
     { 
     for(int i = 0; i < imageNames.size(); i++){ 
      String imageName = imageNames[i] 
      ws('sub-workspace ' + imageName) { 
      echo("Creating ${imageName} container") 
      //unarchive mapping: ['**/sklbr-1.0.0-standalone.tar.gz' : '.', '**/${imageName}/*' : '.', '**/commonConfigs/*' : '.', '**/scripts/*' : '.'] 
      unstash imageName 
      echo("Unstashing ${imageName}") 
      def newApp = docker.build "devops-docker-registry:5000/"+imageName+":${env.BUILD_NUMBER}-${env.SVN_REVISION}" 
      echo("Building container with ${imageName}") 
      newApp.push() 
      echo("Pushing ${imageName} container") 
      } 
     } 
     } 
}

來源

2015-12-11 Cristiano Fontes

嗯，我已經找到了使用shell腳本的方式，但是這不是我一直在尋找...

這萬一你需要

*Nix 
sh 'find /${pwd()} -iname "*" -print0 | xargs -0 echo mv -t a' 

Windows 
bat 'for /r %f in (*) do @move "%f" .'

來源

2015-12-11 11:12:52

JENKINS-29780可能會有所幫助，但要記住，你可以在dir包裹stash和/或unstash。

來源

2015-12-12 10:58:17

謝謝，我會研究它。 –

詹金斯工作流程存放扁平化文件夾

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