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我有一個Json文件,其數據顯示在下面。即時嘗試插入到另一個文件的PHP代碼下面的分貝。我不斷收到錯誤:爲提供的foreach 無效的說法,我不明白爲什麼json to php爲foreach提供的無效參數
[{
"DATE": "02-07-2017",
"TIME": "08:20:48 AM",
"ACCOUNT ID": "1000",
"POSITION": "",
"FIRST NAME": "",
"LAST NAME": "",
"ACCOUNT STATUS": "Active",``
"REAL URL": ""
},{
"DATE": "02-07-2017",
"TIME": "08:20:49 AM",
"ACCOUNT ID": "1000",
"POSITION": "",
"FIRST NAME": "",
"LAST NAME": "",
"ACCOUNT STATUS": "Active",
"REAL URL": ""
},{
"DATE": "02-07-2017",
"TIME": "08:20:49 AM",
"ACCOUNT ID": "1000",
"POSITION": "Ceo",
"FIRST NAME": "",
"LAST NAME": "",
"ACCOUNT STATUS": "Active",
"REAL URL": ""
}]
$JSON_DATA = file_get_contents('Track.js');
$CLEAN_DATA = json_decode($JSON_DATA, true);
$stmt = $db->prepare("INSERT INTO `Track Employee` VALUES (?,?,?,?,?,?,?,?)");
foreach (($CLEAN_DATA) as $row) {
$stmt->bindParam(1, $row['DATE']);
$stmt->bindParam(2, $row['TIME']);
$stmt->bindParam(3, $row['ACCOUNT ID']);
$stmt->bindParam(4, $row['POSITION']);
$stmt->bindParam(5, $row['FIRST NAME']);
$stmt->bindParam(6, $row['LAST NAME']);
$stmt->bindParam(7, $row['ACCOUNT STATUS']);
$stmt->bindParam(8, $row['REAL URL']);
}
帶有.js擴展名的json文件?爲什麼?也從這裏驗證它https://jsonlint.com/,刪除**''** chanracter並添加開始[和結束]括號 –
這是無效的JSON - 它需要包裹在'['和'] '。 – localheinz
您的'json'數據無效 –