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我只是想得到TypeScript的感覺，而且我想將我的代碼分成多個文件。我一直在looking at the documentation，我發現我想用命名空間來尋找。我使用的文件在這裏的例子：有沒有辦法在輸出中結合命名空間？
Validation.ts：
namespace Validation {
export interface StringValidator {
isAcceptable(s: string): boolean;
}
}
LettersOnlyValidator.ts：
/// <reference path="Validation.ts" />
namespace Validation {
const lettersRegexp = /^[A-Za-z]+$/;
export class LettersOnlyValidator implements StringValidator {
isAcceptable(s: string) {
return lettersRegexp.test(s);
}
}
}
ZipCodeValidator.ts：
/// <reference path="Validation.ts" />
namespace Validation {
const numberRegexp = /^[0-9]+$/;
export class ZipCodeValidator implements StringValidator {
isAcceptable(s: string) {
return s.length === 5 && numberRegexp.test(s);
}
}
}
我跟隨該示例並使用tsc我輸出到一個文件。 TypeScript生成此：
var Validation;
(function (Validation) {
var lettersRegexp = /^[A-Za-z]+$/;
var LettersOnlyValidator = (function() {
function LettersOnlyValidator() {
}
LettersOnlyValidator.prototype.isAcceptable = function (s) {
return lettersRegexp.test(s);
};
return LettersOnlyValidator;
}());
Validation.LettersOnlyValidator = LettersOnlyValidator;
})(Validation || (Validation = {}));
var Validation;
(function (Validation) {
var numberRegexp = /^[0-9]+$/;
var ZipCodeValidator = (function() {
function ZipCodeValidator() {
}
ZipCodeValidator.prototype.isAcceptable = function (s) {
return s.length === 5 && numberRegexp.test(s);
};
return ZipCodeValidator;
}());
Validation.ZipCodeValidator = ZipCodeValidator;
})(Validation || (Validation = {}));
var strings = ["Hello", "98052", "101"];
var validators = {};
validators["ZIP code"] = new Validation.ZipCodeValidator();
validators["Letters only"] = new Validation.LettersOnlyValidator();
for (var _i = 0, strings_1 = strings; _i < strings_1.length; _i++) {
var s = strings_1[_i];
for (var name_1 in validators) {
console.log("\"" + s + "\" " + (validators[name_1].isAcceptable(s) ? " matches " : " does not match ") + name_1);
}
}
這工作，但是相當醜陋。有沒有辦法讓它將這兩個塊合併爲一個？