2013-01-31 63 views
1

我必須在MVC4中實現分頁而不回發。我已經用回發實現了分頁。在mvc4中沒有回傳的尋呼

public ActionResult Index(int? page) 
{ 
    var model = from r in db.Country       
       orderby r.Description ascending 
       select r; 
    int pageSize = 10; 
    int pageNumber = (page ?? 1); 
    return View(model.ToPagedList(pageNumber, pageSize));   
} 

和我已經使用在視圖

<div id="pagelist"> 
Page @(Model.PageCount < Model.PageNumber ? 0 : Model.PageNumber) of @Model.PageCount 

@if (Model.HasPreviousPage) 
{ 
    @Ajax.ActionLink("<<", "Index", new { page = 1 },null) 
    @Html.Raw(" "); 
    @Ajax.ActionLink("< Prev", "Index", new { page = Model.PageNumber - 1 },null) 
} 
else 
{ 
    @:<< 
    @Html.Raw(" "); 
    @:< Prev 
} 

@if (Model.HasNextPage) 
{ 
    @Ajax.ActionLink("Next >", "Index", new { page = Model.PageNumber + 1 },null) 
    @Html.Raw(" "); 
    @Ajax.ActionLink(">>", "Index", new { page = Model.PageCount },null) 
} 
else 
{ 
    @:Next > 
    @Html.Raw(" ") 
    @:>> 
} 

此代碼實現尋呼下面的代碼。但每次點擊下一個鏈接時,頁面都會刷新。我希望分頁不刷新頁面。

回答