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我有一個NSString我想要聲明,所以我可以使用它作爲一個applescript。這裏是代碼:特殊字符NSString
NSString *script1 = @"do shell script /usr/bin/php -r ($mac = \"g1:ag:g3:cg:gg:eg\"; $porttemp = \"9\"; $ip = \"255.255.255.255\";
$mac_bytes = explode(\":\", $mac);
$mac_addr = \"\";
for ($i=0; $i<6; $i++)
$mac_addr .= chr(hexdec($mac_bytes[$i]));
$packet = \"\";
for ($i=0; $i<6; $i++) /*6x 0xFF*/
$packet .= chr(255);
for ($i=0; $i<16; $i++) /*16x MAC address*/
$packet .= $mac_addr;
$port = $porttemp;
$sock = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP);
socket_set_option($sock, SOL_SOCKET, SO_BROADCAST, TRUE);
socket_sendto($sock, $packet, strlen($packet), 0, $ip, $port);
socket_close($sock);
);"
我對着它說的Xcode說我不終止它,並給出了一大堆錯誤的問題。任何想法如何我可以解決它或我有什麼問題嗎?
[在程序缺少終端「」字符&Unexpexted @]的可能重複(http://stackoverflow.com/questions/7579781/missing-terminating-character-unexpreted-in-the-program) – Vladimir