上傳sqlite .db文件到服務器時使用哪種內容類型？

Question

我想從我的android應用程序上傳一個.db（SQLite）文件到服務器，我想知道我是否可以使用「multipart/form-data」作爲內容類型。對於「application/pdf」的pdf文件，是否有.db文件的特定類型？

Answer 1

我實際上只是將「multipart/form-data」作爲內容類型來處理它。當我嘗試'application/x-sqlite3'時，出現錯誤。

這裏是代碼片段我用來張貼.db文件服務器，從這個link借：

public int uploadFile(String sourceFileUri) { 

    String fileName = sourceFileUri; // the path to my .db file 

    HttpURLConnection connection = null; 
    DataOutputStream dataOutputStream = null; 
    String lineEnd = "\r\n"; 
    String twoHyphens = "--"; 
    String boundary = "*****"; 
    int bytesRead, bytesAvailable, bufferSize; 
    byte[] buffer; 
    int maxBufferSize = 1 * 1024 * 1024; 
    File sourceFile = new File(sourceFileUri); 

    if (!sourceFile.isFile()) { 

     Log.e("uploadFile", "Source File not exist "); 
     return 0; 
    } else { 
     try { 

      // open a URL connection to the Servlet 
      FileInputStream fileInputStream = new FileInputStream(sourceFile); 
      URL url = new URL(upLoadServerUri); 

      // Open a HTTP connection to the URL 
      connection = (HttpURLConnection) url.openConnection(); 
      connection.setDoInput(true); // Allow Inputs 
      connection.setDoOutput(true); //Triggers http POST method. 

      connection.setUseCaches(false); // Don't use a Cached Copy 
      connection.setRequestMethod("POST"); 
      connection.setRequestProperty("Connection", "Keep-Alive"); 
      connection.setRequestProperty("ENCTYPE", "multipart/form-data"); 
      connection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary); 
      //conn.setRequestProperty("Content-Type", "application/x-sqlite3; boundary=" + boundary);// when I tried this it didn't work, so you can delete this line 
      connection.setRequestProperty("uploadedfile", fileName); 

      dataOutputStream = new DataOutputStream(connection.getOutputStream()); 

      dataOutputStream.writeBytes(twoHyphens + boundary + lineEnd); 
      dataOutputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=" + fileName + "" + lineEnd); 
      dataOutputStream.writeBytes(lineEnd); 

      // create a buffer of maximum size 
      bytesAvailable = fileInputStream.available(); 

      bufferSize = Math.min(bytesAvailable, maxBufferSize); 
      buffer = new byte[bufferSize]; 

      // read file and write it into form... 
      bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

      while (bytesRead > 0) { 

       dataOutputStream.write(buffer, 0, bufferSize); 
       bytesAvailable = fileInputStream.available(); 
       bufferSize = Math.min(bytesAvailable, maxBufferSize); 
       bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

      } 

      // send multipart form data necesssary after file data... 
      dataOutputStream.writeBytes(lineEnd); 
      dataOutputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 

      // Responses from the server (code and message) 
      serverResponseCode = connection.getResponseCode(); 
      String serverResponseMessage = connection.getResponseMessage(); 

      Log.i("uploadFile", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode); 

      if (serverResponseCode == 200) { 

       String msg = "server respose code "; 
       Log.i(TAG, msg + serverResponseCode); 
       StringBuilder result = new StringBuilder(); 

       InputStream in = new BufferedInputStream(connection.getInputStream()); 

       BufferedReader reader = new BufferedReader(new InputStreamReader(in)); 

       String line; 
       while ((line = reader.readLine()) != null) { 
        result.append(line); 
       } 

       //JSONObject mResponseJSONObject = new JSONObject(String.valueOf(result)); //convert the respons in json 
       Log.i(TAG, msg + result); 
      } 

      //close the streams // 
      fileInputStream.close(); 
      dataOutputStream.flush(); 
      dataOutputStream.close(); 

     } catch (MalformedURLException ex) { 
      ex.printStackTrace(); 
      Log.e(TAG, "MalformedURLException Exception : check script url."); 
      Log.e("Upload file to server", "error: " + ex.getMessage(), ex); 
     } catch (Exception e) { 
      e.printStackTrace(); 
      Log.e(TAG, "Upload file to server Exception : " + e.getMessage(), e); 
     } 

     return serverResponseCode; 

    } // End else block 
} //[End uploadFileToServer method] 

這是我在服務器端使用PHP腳本：

<?php 
if(isset($_FILES)) { 
    if(move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], "./data/".$_FILES["uploadedfile"]["name"]."_".time())) { 

      echo " file recieved successfully" 
      exit; 
    } 
} 
echo "Error"; 

?>