iOS模擬器上的UITapGestureRecognizer崩潰

Question

當我嘗試使用UITapGestureRecognizer時，我的iOS模擬器崩潰。

這是我的手勢：

UITapGestureRecognizer tap = new UITapGestureRecognizer (new NSAction(delegate { 
    if(SettingsTapped != null){ 
    SettingsTapped(this, EventArgs.Empty); 
    } 
})); 

我加入這個手勢一個UIView，然後添加該視圖一個UITableViewCell。 觸摸視圖（每次）後該應用程序崩潰，顯示沒有例外。

她是從模擬器的日誌文件輸出：

Nov 4 10:49:47 administorsmini xXxXx[11073]: assertion failed: 13E28 12B411: libsystem_sim_trace.dylib + 19982 [BEE53863-0DEC-33B1-BFFB-8F7AE595CC73]: 0x4 
Nov 4 10:49:49 administorsmini xXxXx[11073]: Stacktrace: 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at <unknown> <0xffffffff> 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at (wrapper managed-to-native) MonoTouch.UIKit.UIApplication.UIApplicationMain (int,string[],intptr,intptr) <IL 0x000a6, 0xffffffff> 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at MonoTouch.UIKit.UIApplication.Main (string[],intptr,intptr) [0x00005] in /Developer/MonoTouch/Source/monotouch/src/UIKit/UIApplication.cs:62 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at MonoTouch.UIKit.UIApplication.Main (string[],string,string) [0x00038] in /Developer/MonoTouch/Source/monotouch/src/UIKit/UIApplication.cs:46 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at xXxXx.Application.Main (string[]) [0x00008] in /Users/Norman/Desktop/xXxXx/xXxXx/Main.cs:17 
Nov 4 10:49:49 administorsmini xXxXx[11073]: at (wrapper runtime-invoke) <Module>.runtime_invoke_void_object (object,intptr,intptr,intptr) <IL 0x00050, 0xffffffff> 
Nov 4 10:49:49 administorsmini xXxXx[11073]: 
Native stacktrace: 
Nov 4 10:49:49 administorsmini xXxXx[11073]: 
================================================================= 
Got a SIGSEGV while executing native code. This usually indicates 
a fatal error in the mono runtime or one of the native libraries 
used by your application. 
================================================================= 
Nov 4 10:49:49 administorsmini com.apple.CoreSimulator.SimDevice.27B5D497-B641-4BCA-8FA0-EF9E28E07143.launchd_sim[10951] (UIKitApplication:com.your-company.xXxXx[0x7041][11073]): Service exited due to signal: Abort trap: 6 
Nov 4 10:49:49 administorsmini SpringBoard[10962]: Application 'UIKitApplication:com.your-company.xXxXx[0x7041]' crashed. 
Nov 4 10:49:49 administorsmini assertiond[10966]: notify_suspend_pid() failed with error 7 
Nov 4 10:49:49 administorsmini assertiond[10966]: assertion failed: 13E28 12B411: assertiond + 11523 [3F572A0B-7E12-378D-AFEE-EA491BAF2C36]: 0x1 

我現在該怎麼辦？ 我不想要開發的設備...

編輯

我最終通過重寫的UIView，並使用其TouchesBegan()方法。 有許多方法可以使點擊的東西，但我爲什麼不能只使用這個上面？

Answer 1

下面是我'用我的應用程序

private void addTapGesture() 
    { 
     imgLogo.UserInteractionEnabled = true; 
     var tapGesture = new UITapGestureRecognizer(this, new Selector("ResendTrigger:")); 
     tapGesture.NumberOfTapsRequired = 5; 
     imgLogo.AddGestureRecognizer(tapGesture);   
    } 
    [Export("ResendTrigger:")] 
    public void ResendTrigger(UIGestureRecognizer sender) 
    { 
     System.Diagnostics.Debug.WriteLine("Triggered");} 

構造函數的第一個參數（這個）指向對象，其中包含與特定屬性導出方法的定義，因此，如果您將定義選擇的碼位和方法在你的視圖中NSObject目標將是你的視圖的引用，如果你想調用的方法存在於例如單元格中，你的單元格引用將成爲目標。

編輯

基於評論我假設你可能正在使用UITableViewSource。我認爲你的情況與我的類似，所以試試這種方法：

在你的UITableSource中聲明事件
public event EventHandler<DataBaseModels.SavedActions> OnActionSelected;
然後在getCell中爲你的視圖和內部方法分配點擊手勢，你將引用sender對象，將其轉換爲UIView，保留標記以標識相應的記錄