我想要做的是當我點擊提交按鈕,並嘗試獲取它沒有正確顯示的值。我書面方式2文件的代碼下1)enable.php 2)abc.phponlick更改下拉框中的名稱
文件名:enable.php
<html>
<head>
<script type="text/javascript">
function showdetail(boxid){
document.getElementById(boxid).style.display = "block";
}
function hidedetail(boxid){
document.getElementById(boxid).style.display = "none";
}
</script>
</head>
<body>
<form name="abc" method="post" action="abc.php">
<ul>
<li><a id="r" href="#" title="" alt="" onclick="showdetail('res'); hidedetail('comm');">bb</a></li>
<li style="width: 1px;">|</li>
<li style="width:85px;"><a id="r" href="#" title="" alt="" onclick="showdetail('comm'); hidedetail('res');">Cc</a></li>
<li style="width: 2px;">|</li>
</ul>`
<div id="res" style="display:none;">
<select id="pr" name="pr" class="textarial12 textcolorgrey flot_left">
<option value="Hello">Hello</option>
</select>
</div>
<div id="comm" style="display:none;">
<select id="pr" name="pr" class="textarial12 textcolorgrey flot_left">
<option value="Hi">Hi</option>
</select>
</div>
<input type="submit" value="submit" />
</form>
</body>
</html>
文件名:abc.php
<?php
$PropertyType=$_POST[pr];
echo $PropertyType;
?>
當你點擊提交按鈕 – Drake