更新列值從mysql_fetch_array結果PHP

Question

我想從mysql_fetch_array

但最後的結果更新從MySQL表，結果一列的值僅僅是被插入一個/更新到列

我在哪裏錯了？這是我的代碼。在此先感謝

$studentname="some value"; 
    $course="some value"; 
    $query=mysql_query("select SABJEK,GRADE,REMARKS from table where STUDENTNAME='$studentname' && STUDENTNUMBER IS NULL") or die(mysql_error()); 
    while($result=mysql_fetch_array($query)) 
     { 
     $sabjek=$result['SABJEK']; 
     $grade=$result['GRADE']; 
     $remarks=$result['REMARKS']; 
     $msg="$sabjek = $grade - $remarks "; 
     $msg1="$studentname $course $msg"; 
     } 
    mysql_query("update table2 set `msg`='$msg1' where studentname='$studentname'") or die(mysql_error()); 

Answer 1

將mysql_query放在while中。基本上取代

} 
mysql_query("update table2 set `msg`='$msg1' where studentname='$studentname'") or die(mysql_error()); 

與

mysql_query("update table2 set `msg`='$msg1' where studentname='$studentname'") or die(mysql_error()); 
} 

，它會工作:)

Answer 2

If you want to update the column name every-time whenvere you fetch the result just put update query inside the while loop, 
    $studentname="some value"; 
    $course="some value"; 
    $query=mysql_query("select SABJEK,GRADE,REMARKS from table where STUDENTNAME='$studentname' && 
    STUDENTNUMBER IS NULL") or die(mysql_error()); 
    while($result=mysql_fetch_array($query)); 
    { $sabjek=$result['SABJEK']; 
     $grade=$result['GRADE']; 
     $remarks=$result['REMARKS']; 
     $msg="$sabjek = $grade - $remarks "; 
     $msg1="$studentname $course $msg";   
     mysql_query("update table2 set `msg`='$msg1' where studentname='$studentname'") or   
     die(mysql_error()); 
    } 

，如果你不希望這樣的結果，那麼請給我解釋一下詳細的話，我會更新的答案。

謝謝。