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我創建了一個新的Spring MVC項目，然後在index.jsp中發送POST到名爲springController.java的Spring Controller。文件的index.jsp：
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script type="text/javascript" src="//code.jquery.com/jquery-1.10.2.js"></script>
<script type="text/javascript" src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<title>Welcome to Spring Web MVC project</title>
<script type="text/javascript">
$(document).ready(function(){
$("#testForm").submit(onFormSubmit);
});
function onFormSubmit(e){
data = $("#testForm").serialize();
// console.log(data);
$.post("/test/another");
e.preventDefault();
}
</script>
</head>
<body>
<form id="testForm">
<label>Imie: </label>
<input type="text" name="login">
<label>Nazwisko: </label>
<input type="text" name="password">
<input id="testPostButton" type="submit">
</form>
</body>
</html>
我試圖抓住POST在springController.java，這裏是代碼：
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package newpackage;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
/**
*
* @author Abc
*/
@Controller
@RequestMapping(/*method=RequestMethod.POST,*/ "/test")
public class springController {
/**
*
* @return
*/
@RequestMapping(/*method=RequestMethod.POST,*/ "/another")
@ResponseBody
public void test(){
System.out.println("Doszlo");
}
}
但sendind POST不工作，在WebInspector控制檯我得到
POST http://localhost:8084/test/another 404 (Not Found)
在這一刻我只想抓取從index.jsp發送的POST。不幸的是，我是Spring MVC的新手，我不知道我做錯了什麼。 這裏是調度員servlet.xml中：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<!--
Most controllers will use the ControllerClassNameHandlerMapping above, but
for the index controller we are using ParameterizableViewController, so we must
define an explicit mapping for it.
-->
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="index.htm">indexController</prop>
</props>
</property>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
<bean name="/test" class="newpackage.springController"/>
這裏是web.xml中：
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
</web-app>
我不知道什麼是錯的，我爲什麼不能,,抓「在springController.java中從index.jsp發佈POST 這是我在StackOverflow上的第一篇文章，如果有人決定幫助我，我會非常高興
來自波蘭的問候並感謝您的幫助！
這裏是文件applicationContext，我必須在這裏粘貼文件，因爲我是新的，沒有足夠的信譽。仍然在WebInspector控制檯我有同樣的消息早前：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd">
<context:component-scan base-package="by" use-default-filters="false">
<context:include-filter expression="org.springframework.stereotype.Controller" type="annotation"/>
</context:component-scan>
<mvc:annotation-driven />
</beans>
不幸的是，仍然無法正常工作，也許我貼你在錯誤的地點的代碼，文件的applicationContext我有在第一篇文章中粘貼，因爲回覆消息太長，我沒有足夠的信譽來回答自己。 –
抱歉，嘗試將的「base-package」屬性從「by」更改爲「newpackage」（您的類所在的包）。 –
yname