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我嘗試從接觸list.Here電話號碼和聯絡電話號碼是我的代碼,以顯示它...獲得來自聯繫人列表的名稱和數量
public class ContactTutorialActivity extends Activity {
/** Called when the activity is first created. */
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE);
startActivityForResult(intent, 1);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (data != null) {
Uri uri = data.getData();
if (uri != null) {
Cursor c = null;
try {
c = getContentResolver().query(uri, new String[]
{
ContactsContract.CommonDataKinds.Phone.NUMBER,ContactsContract.CommonDataKinds.Phone.TYPE },null, null, null);
if (c != null && c.moveToFirst()) {
String number = c.getString(0);
int type = c.getInt(1);
showSelectedNumber(type, number);
}
} finally {
if (c != null) {
c.close();
}
}
}
}
}
public void showSelectedNumber(int type, String number)
{
Toast.makeText(this, type + " " + number, Toast.LENGTH_LONG).show();
}
}
那麼我希望是,如果我選擇任何的光標移動到第一個並顯示選定的名稱和編號 但在這裏當我運行程序光標移動到第一個吐司消息work.no聯繫人名稱和編號。