apache fileupload parserequest不返回文件列表

Question

我想公開REST服務的文件上傳和編寫REST客戶端調用服務。我使用apache fileupload來使用文件，因爲我當前的應用程序是舊的，並且屬於2.5的servlet api時代。當我調用ServletFileUpload的parseRequest方法時，它不會從請求中返回任何文件並拋出Error對象。該應用程序還支持Spring 4

REST客戶端

HttpHeaders httpHeaders = new HttpHeaders(); 
httpHeaders.setContentType(MediaType.MULTIPART_FORM_DATA); 
MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>(); 

parts.add("file", new ByteArrayResource(file.getBytes())); 
parts.add("path", "C:/Temp/link.txt"); 

RestTemplate restTemplate = new RestTemplate(); 
HttpHeaders headers = new HttpHeaders(); 
headers.setContentType(MediaType.MULTIPART_FORM_DATA); 
headers.setContentDispositionFormData("filename","link.txt"); 

HttpEntity<MultiValueMap<String, Object>> requestEntity = new HttpEntity<MultiValueMap<String, Object>>(parts, headers); 
ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:9080/contextroot/restservice.htm",requestEntity, String.class); 

Servlet的REST服務

@RequestMapping(value = "restservice.htm") 
public ResponseMessage restservice(HttpServletRequest request, 
     HttpServletResponse response) throws IOException, ServletException, FileUploadException { 



    if(ServletFileUpload.isMultipartContent(request)) { 
     FileItemFactory factory = new DiskFileItemFactory(); 
     ServletFileUpload upload = new ServletFileUpload(factory); 
     List<FileItem> fileList = upload.parseRequest(request); 

     System.out.println("Headers : "); 
     Enumeration<String> headerEnumeration = request.getHeaderNames(); 
     while(headerEnumeration.hasMoreElements()) { 
      String headerName = headerEnumeration.nextElement(); 
      System.out.println("Name : " + headerName + ", Value : " + request.getHeader(headerName)); 
     } 

     System.out.println("Parameters : "); 
     Enumeration<String> paramEnumeration = request.getParameterNames(); 
     while(paramEnumeration.hasMoreElements()) { 
      String paramName = paramEnumeration.nextElement(); 
      System.out.println("Name : " + paramName + ", Value : " + request.getParameter(paramName)); 
     } 

     if(null == fileList || fileList.isEmpty()) { 
      //Setting ERROR 
     } 
     else { 
      //Setting SUCCESS 
     } 
    } 
    else { 
      //Setting ERROR 
    } 


    return message; 
} 

和輸出的頭是

Name : Accept, Value : text/plain, application/json, application/*+json, */* 
Name : Content-Type, Value : multipart/form- data;boundary=CqVx3AfV3oq7XjEPmPkWXqve9lNs3Ntjhz1kBaI 
Name : Content-Disposition, Value : form-data; name="filename"; filename="link.txt" 

請求參數同時包含路徑和文件引用。

Answer 1

我使用XMLRootElement創建了對象，並在對象內發送了文件引用。使用REST服務很快選擇文件參考。

REST客戶

File srcFile = new File("C:/Temp/hellotest.jpg"); 
FileInputStream inputStream = new FileInputStream(srcFile); 
byte[] bytes = IOUtils.toByteArray(inputStream);    
inputStream.close(); 
FileInfo requestEntity = new FileInfo(); 
requestEntity.setPath("C:/Temp/hellotest12.jpg"); 
requestEntity.setContent(bytes); 
RestTemplate restTemplate = new RestTemplate();     
ResponseEntity<String> response = restTemplate.postForEntity("http://localhost:9080/contextroot/restservice.htm",requestEntity, String.class); 

REST服務

@RequestMapping(value = "restservice.htm") 
public String restservice(@RequestBody FileInfo fileInfo, HttpServletResponse response, HttpServletRequest request) { 
    LOG.info("File created @ " + fileInfo.getPath()); 
    File file = new File(fileInfo.getPath()); 

    OutputStream outputStream = new FileOutputStream(file); 
    IOUtils.write(fileInfo.getContent(), outputStream); 
    outputStream.flush(); 
    outputStream.close(); 


    return message; 
}