Junit無效驗證方法

我有一個簡單的驗證來驗證客戶端不存在具有相同的屬性，只有驗證有2個選項： 1.如果滿足某些條件拋出驗證異常。 2.否則返回void。Junit無效驗證方法

像這樣：

public class ClientValidator { 
    private ClientFinder clientFinder; 
    protected void validate(final Client client) throws ValidationException 
    { 
     final Client existingClient = clientFinder.getClientByAttributes(client.getAttr1(), 
     client.getAttr2()); 
     if (existingClient != null && ! existingClient.getId().equals(client.getId())) 
     { 
      throw new ValidationException("Client Exists with the same attributes")); 
     } 
    } 
    //getters and setters 

}  
}

了JUnit：

@UnitTest 
@RunWith(MockitoJUnitRunner.class) 
public class ValidatorTest 
{ 
    private ClientValidator validator; 

    @Mock 
    private ClientFinder clientFinder; 
    private Client existingClient; 
    private Client newClient; 
    private static final String ATTR1 = "ATTR1"; 
    private static final String ATTR2 = "ATTR2"; 

    @Before 
    public void setup() 
    { 
     existingClient = new Client("ID1", ATTR1, ATTR2); 
     newClient = new Client("ID2", ATTR1, ATTR2); 


     validator = new ClientValidator(); 
     validator.setClientFinder(clientFinder); 
    } 

    @Test(expected = ValidatorException.class) 
    public void testCreatingNewClient() throws ValidationException 
    { 
     //the service will find other Client than the one being created 
     Mockito.when(clientFinder.getClientByAttributes(ATTR1, ATTR2)).thenReturn(existingClient); 
     validator.onValidate(newClient); 
    } 



    @Test() 
    public void testModifyExistingClient() throws ValidationException 
    { 
     //the service will find the same Client being modified 
     Mockito.when(clientFinder.getClientByAttributes(ATTR1, ATTR2)).thenReturn(newClient); 
     validator.onValidate(newClient); //No exception should be thrown 
    } 


}

第二確認是可能發生的情況之一，是第二個驗證不必要的由於沒有斷言？有沒有辦法驗證這個第二個條件？

來源

2014-04-07 user3294598