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這是問題的html,問題基本上是當我點擊datatable第一頁上的userimage類,然後它工作正常,但是當我點擊datatable的第二頁然後even不被解僱。Jquery不工作在數據表的第二頁
<table class="table" id="example1">
<thead>
<tr>
<th>S.No.</th>
<th>Name</th>
<th>Email</th>
<th>Contact</th>
<th>Action</th>
</tr>
</thead>
<tbody>
<?php
$i = 0;
foreach($users as $user){
$i++;
$id = $user['id'];
$btn_class = ($user['status'] ==1 ? "btn btn-success" : "btn btn-warning");
$url_attribute = ($user['status'] ==1 ? "user-disable" : "user-enable");
$btn_text = ($user['status'] ==1 ? "Disable" : "Enable");
$picture = $_SERVER['DOCUMENT_ROOT']. "/temp/assets/images/user_profile/". $user['image'];
$user_profile_pic = (file_exists($picture) && $user['image'] != "" ? base_url()."/temp/assets/images/user_profile/". $user['image'] : ($user['social_image'] ? $user['social_image'] : ""));
?>
<tr>
<td><?= $i;?></td>
這是在其click事件被觸發的userimage類。
<td <?php if($user_profile_pic != ""){ ?> class="userimage" data-userimage="<?= $user_profile_pic;?>">
<a data-toggle="modal" data-target="#myModal" href="" <?php } ?>>
<?= ($user['fulname'] ? $user['fulname'] : "N/A"); ?></a>
</td>
<td><?= ($user['email'] ? $user['email'] : "N/A");?></td>
<td><?= ($user['contact'] ? $user['contact'] : "N/A");?></td>
<td>
<a href="<?= base_url().'admin/user-view/'.$id;?>" class="btn btn-info">View Detail</a>
<a href="<?= base_url().'admin/user-delete/'.$id;?>" class="btn btn-danger" onclick="return confirm_delete();">Delete</a>
<a href="<?= base_url().'admin/'.$url_attribute.'/'.$id;?>" class="<?= $btn_class;?>"><?= $btn_text;?></a>
</td>
</tr>
<?php
}
?>
</tbody>
</table>
這是JavaScript代碼。
<script type="text/javascript">
function confirm_delete(){
var x = confirm("Are You Sure, you want to delete this User ?");
if(x){
return true;
}else{
return false;
}
}
$("#example1").DataTable();
$(".userimage").click(function(){
var image = $(this).attr('data-userimage');
var name = $(this).text().toUpperCase();
$("#image").show();
$("#image").attr('src',image);
$("#fulname").text(name);
})
</script>
而不是像這樣粘貼代碼使用小提琴,snippet或plunkr來複制你的問題 –