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我使用jQuery UI獲取朋友姓名和編號的建議,但問題是我不能使用自動完成json函數傳遞用戶標識。jquery ui自動完成傳遞變量
$(function() {
function split(val) {
return val.split(/,\s*/);
}
function extractLast(term) {
return split(term).pop();
}
$("#recipient")
// don't navigate away from the field on tab when selecting an item
.bind("keydown", function(event) {
if (event.keyCode === $.ui.keyCode.TAB &&
$(this).data("autocomplete").menu.active) {
event.preventDefault();
}
})
.autocomplete({
source: function(request, response) {
var attm= $('.USERID').val();
$.getJSON("modules/messages/sql.php", {
term: extractLast(request.term),
}, response);
},
search: function() {
// custom minLength
var term = extractLast(this.value);
if (term.length < 2) {
return false;
}
},
focus: function() {
// prevent value inserted on focus
return false;
},
select: function(event, ui) {
var terms = split(this.value);
// remove the current input
terms.pop();
// add the selected item
terms.push(ui.item.value);
// add placeholder to get the comma-and-space at the end
terms.push("");
this.value = terms.join(", ");
var prollNos = $('#recipientid').val()
$('#recipientid').val(prollNos + ui.item.id + ", ");
return false;
}
});
});
在我試圖傳遞一個:$('.USERID').val()
如用戶ID,任何人都可以幫我嗎?
$('。USERID')。val()從哪裏來?請更多代碼。 –
m通過jquery val() –