無法與效果，請使用JSON.parse從json_encode

在我的PHP文件，我有以下代碼無法與效果，請使用JSON.parse從json_encode

//create SQL to select schedule 
$sql = "SELECT * FROM `Schedule`"; 

//create result set 
$result = mysql_query($sql); 

$result_array[] = ""; 
while($row = mysql_fetch_assoc($result)) 
{ 
    $result_array[$row['ID']] = $row; 
} 

echo json_encode($result_array);

在我的HTML文件中，我有以下代碼

xmlhttp.onreadystatechange=function() 
    { 
    if (xmlhttp.readyState==4 && xmlhttp.status==200) 
    { 
    var schedArray = JSON.parse(xmlhttp.ResponseText); 

    alert(schedArray[0]["ID"]); 
    } 
    } 
    xmlhttp.open("GET","getSchedule.php?q="+year,true); 
    xmlhttp.send();

當我運行我的HTML代碼我得到這個錯誤：Uncaught SyntaxError：意外的代幣ü

我相信我的數據編碼正確，因爲運行

document.getElementById("txtHint").innerHTML=xmlhttp.responseText;

在我準備狀態檢查網我用正確的數據數組：

{"0":"","1":{"ID":"1","Team":"Louisiana-Monroe","playDate":"2011-09-03","Conference":"Sun Belt","Rank":null,"Bowl":"0","Site":"H"},"3":{"ID":"3","Team":"Oklahoma","playDate":"2011-09-17","Conference":"Big 10","Rank":"1","Bowl":"0","Site":"H"},"4":{"ID":"4","Team":"Clemson","playDate":"2011-09-24","Conference":"ACC","Rank":"21","Bowl":"0","Site":"A"},"5":{"ID":"5","Team":"Wake Forest","playDate":"2011-10-08","Conference":"ACC","Rank":null,"Bowl":"0","Site":"A"},"6":{"ID":"6","Team":"Duke","playDate":"2011-10-15","Conference":"ACC","Rank":null,"Bowl":"0","Site":"A"},"7":{"ID":"7","Team":"Maryland","playDate":"2011-10-22","Conference":"ACC","Rank":null,"Bowl":"0","Site":"H"},"8":{"ID":"8","Team":"North Carolina State","playDate":"2011-10-29","Conference":"ACC","Rank":null,"Bowl":"0","Site":"H"},"9":{"ID":"9","Team":"Boston College","playDate":"2011-11-03","Conference":"ACC","Rank":null,"Bowl":"0","Site":"A"},"10":{"ID":"10","Team":"Miami (FL)","playDate":"2011-11-12","Conference":"ACC","Rank":null,"Bowl":"0","Site":"H"},"11":{"ID":"11","Team":"Virginia","playDate":"2011-11-19","Conference":"ACC","Rank":null,"Bowl":"0","Site":"H"},"12":{"ID":"12","Team":"Florida","playDate":"2011-11-26","Conference":"SEC","Rank":null,"Bowl":"0","Site":"A"},"13":{"ID":"13","Team":"Notre Dame","playDate":"2011-12-29","Conference":"IND","Rank":null,"Bowl":"1","Site":"N"},"14":{"ID":"14","Team":"Murray State","playDate":"2012-09-01","Conference":"Ohio Valley","Rank":null,"Bowl":"0","Site":"H"},"15":{"ID":"15","Team":"Savannah State","playDate":"2012-09-08","Conference":"MEAC","Rank":null,"Bowl":"0","Site":"H"}}

我想不通爲什麼我收到此錯誤。我沒有使用JQuery，並且在我的JavaScript中包含了json2.js。任何人可以提供的幫助都會很好。

來源

2012-09-05 evenflow58

您的縮寫可能隱藏了JSON中的實際錯誤。還有真正用作屬性名稱的空字符串嗎？ – Pointy

你可以在編碼後發佈JSON嗎？ – LmC

多數民衆贊成沒有任何幫助，你可以提供您正在嘗試解析的完整JSON – LmC

你的問題，我認爲，在這裏：

應該responseText，小寫字母「R」。發生什麼事是字符串"undefined"是解析器實際上試圖解釋的內容，而以「u」開頭的字符串不能是有效的JSON。

你在填充調試元素以顯示響應的代碼中是正確的。

來源

2012-09-05 15:24:16 Pointy

+1，確實不錯，我只看了最後一個'responseText' :) – Jon

那幫了！我將其更改爲小寫字母r，並停止發現該錯誤。不幸的是，我現在得到意外的標記<當我註釋掉JSON.parse行時，我不會收到錯誤。 – evenflow58

那麼你發佈的JSON中沒有'<'字符，所以這沒有什麼意義。 – Pointy

構造結果的代碼是錯誤的。它應該閱讀：

$result_array = array(); 
while($row = mysql_fetch_assoc($result)) 
{ 
    $result_array[$row['id']] = $row; 
}

來源

2012-09-05 15:15:47 Jon

我在那裏添加Num的原因是因爲我只返回一個結果。我相信它會覆蓋$ result_array。我的'echo json_encode（$ result_array）'的輸出是{「0」：「」，「」：{「ID」：「15」，「Team」：「Savannah State」，「playDate」：「 2012-09-08「，」Conference「：」MEAC「，」Rank「：null，」Bowl「：」0「，」Site「：」H「}} – evenflow58

@ evenflow58：在這種情況下，唯一的解釋是原始代碼是誤導性的，'$ row'不*具有'id'鍵。你確定它是'id'而不是'ID'嗎？什麼是表格列的*精確*名稱？ – Jon

@Jon我認爲我發現了這個問題，但我同意你的觀點，即響應對象的構建方式有問題。 – Pointy

無法與效果，請使用JSON.parse從json_encode

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