電腦猜我編號C編程

Question

誰能告訴我我的代碼有什麼問題。我正在嘗試創建一個遊戲，讓電腦猜測我輸入的數字。這裏是我的代碼：

---

#include <stdio.h> 
#include <time.h> 
#include <stdlib.h> 

int main(void) { 

int numberGuess = 0; 
int low = 1; 
int high = 100; 
int computerGuess = 0; 

printf("Enter a number, 1 - 100: "); 
scanf("%d", &numberGuess); 

while (computerGuess != numberGuess) 
{ 

    computerGuess = ((high - low) + low)/2; 
    printf("%d ", computerGuess); 

    if (numberGuess > computerGuess) 
    { 
    printf("Your guess was to low \n"); 
    low = computerGuess+1; 
    } 
    else if (numberGuess < computerGuess) 
    { 
    printf("Your guess was to high \n"); 
    high = computerGuess-1; 
} 
    else if (numberGuess == computerGuess) 
{ 
printf("Yess!! you got it!\n"); 
    } 
} 
return 0; 
} 

Answer 1

computerGuess = ((high - low) + low)/2; 

在這裏你只需要添加低，然後imidiately。減去從而使代碼等於

computerGuess = ((high)/2; 

，你總是比較相同的值while循環永不結束。

Answer 2

這一行：

computerGuess = ((high - low) + low)/2; 

應該是：

computerGuess = (high - low)/2+low; 

你所尋找的是你的高和低（這是一個二進制搜索，但我的數一半當然你知道）。

Answer 3

修復代碼：

#include <time.h> 
#include<stdio.h> 
#include <stdlib.h> 

int main(void) { 

int numberGuess = 0; 
int low = 1; 
int high = 100; 
int computerGuess = 0; 

printf("Enter a number, 1 - 100: "); 
scanf("%d", &numberGuess); 

while (computerGuess != numberGuess) 
{ 

    computerGuess = ((high - low)/2 + low); 
    printf("%d ", computerGuess); 

    if (numberGuess > computerGuess) 
    { 
    printf("Your guess was to low \n"); 
    low = computerGuess+1; 
    } 
    else if (numberGuess < computerGuess) 
    { 
    printf("Your guess was to high \n"); 
    high = computerGuess-1; 
} 
    else if (numberGuess == computerGuess) 
{ 
printf("Yess!! you got it!\n"); 
    } 
} 

return 0; 
}