選擇成JSON

Question

下我的問題

是更多鈔票來選擇值到我的JSON對象，它的意思是要列出不同的學校，其中aaa研究

JSON對象看起來像這樣

[{」名稱「：」aaa「，」0「：」aaa「，」city「：」paris「，」1「：」paris「，」school「：」gtdzh「，」2「：」gtdzh「名稱「：」bbb「，」0「：」bbb「，」city「：」berlin「，」1「：」berlin「，」school「：」gdezh「，」2「：」gdezh「}，{」名稱「：」ccc「，」0「：」ccc「，」city「：」new york「，」1「：」new york「，」school「：」asdzh「，」2「：」asdzh「 { 「名」： 「AAA」， 「0」： 「AAA」， 「城市」： 「悉尼」， 「1」： 「悉尼」， 「學校」： 「gtdcv」 「2」：「gtdcv」}，{「名稱」：「bbb」，「0」：「bbb」，「城市」：「巴黎」，「1」：「巴黎」，「學校」：「gtdzh」， 「2」：「gtdzh」}]

感謝您的幫助

Answer 1

如果所有的名字都可以保證是唯一的，那麼你可以做這樣的事情：

var data_array = [ 
{"name":"aaa","0":"aaa","city":"paris","1":"paris","school":"gtdzh","2":"gtdzh"}, 
{"name":"bbb","0":"bbb","city":"berlin","1":"berlin","school":"gdezh","2":"gdezh"}, 
{"name":"ccc","0":"ccc","city":"new york","1":"new york","school":"asdzh","2":"asdzh"}, 
{"name":"aaa","0":"aaa","city":"sidney","1":"sidney","school":"gtdcv","2":"gtdcv"}, 
{"name":"bbb","0":"bbb","city":"paris","1":"paris","school":"gtdzh","2":"gtdzh"} 
]; 

var l = data_array.length; 
var i = 0 

// We will use dict to store our output 
var dict = {}; 

// Loop over the entire array 
while (i < l) { 
    // Grab references to everything we need 
    var name = data_array[i].name; 
    var city = data_array[i].city; 

    // If we haven't seen this person before, add them to the dict 
    if (! Object.prototype.hasOwnProperty.call(dict, name)) { 
     dict[name] = {}; 
    } 

    // Similarly, if we haven't heard of them studying in this city yet 
    // add that city to the "dictionary" of cities they've studied in 
    // and set the count of times they have studied in that city to 1. 
    if (! Object.prototype.hasOwnProperty.call(dict[name], city)) { 
     dict[name][city] = 1; 
    // Otherwise, increment the number of times they have studied in that city. 
    } else { 
     dict[name][city] += 1; 
    } 
    i++; 
} 

的最終結果將如下所示：

dict = { 
    "aaa": { 
     "paris": 1, 
     "sidney": 1 
    }, 
    "bbb": { 
     "berlin": 1, 
     "paris": 1 
    }, 
    "ccc": { 
     "new york": 1 
    } 
}; 

當然，如果你反覆做這類事情的話，更好的方法是 - 從改變數據從服務器發送到構建或使用諸如Underscore等幫助程序庫來完成這種數據傳輸的方式。這裏也有一些Javascript數據庫實現，但是我沒有與其中任何一個一起工作，所以我不能在這方面推薦任何東西。