1
問題是我無法用next()讀取變量輸入,當我嘗試拆分(.split「」)每個空白,然後數組只是得到前兩個單詞I鍵入所以我不得不使用keyboard.nextLine()和分裂過程的工作方式,它應該工作,我得到的數組中的所有單詞,但問題是,如果我使用nextLine(),那麼我必須創建另一個鍵盤對象讀第一個變量(答案),這是我可以在這裏工作的唯一方法是代碼閱讀字符串next()和nextLine()Java
Scanner keyboard=new Scanner(System.in);
Scanner keyboard2=new Scanner(System.in);//just to make answer word
int answer=keyboard.nextInt();//if I don't use the keyboard2 here then the program will not work as it should work, but if I use next() instead of nextLine down there this will not be a problem but then the splitting part is a problem(this variable counts number of lines the program will have).
int current=1;
int left=0,right=0,forward=0,back=0;
for(int count=0;count<answer;count++,current++)
{
String input=keyboard.nextLine();
String array[]=input.split(" ");
for (int counter=0;counter<array.length;counter++)
{
if (array[counter].equalsIgnoreCase("left"))
{
left++;
}
else if (array[counter].equalsIgnoreCase("right"))
{
right++;
}
else if (array[counter].equalsIgnoreCase("forward"))
{
forward++;
}
else if (array[counter].equalsIgnoreCase("back"))
{
back++;
}
}
}
}
謝謝:)
請問您可以編輯您的問題以包含標點符號。真的很難理解你的問題是什麼。 – 2012-01-15 21:12:47