刪除所有字母和逗號從字符串

Question

我有一個包含多個元素，看起來像這樣一個巨大的名單：

'A.21,48;B.64,91;C.95,125;D.139,166;E.175,200'

我想去除所有字母和; .字符和追加到一個列表，例如該列表看起來像['21','48','64','91','95','125','139','166','175','200']

我試着使用：

import re 
list.append(re.sub("\D","", <the string i am working on>)) 

但[R在這樣的列表中結果 - [' 21 48 64 91 95 125 139 166 175 200']

因爲我在一個非常大的文件循環內工作，一行代碼將真正有用。

謝謝

Answer 1

您可以使用re.findall()：

>>> import re 
>>> strs='A.21,48;B.64,91;C.95,125;D.139,166;E.175,200' 
>>> re.findall(r"\d+",strs) 
['21', '48', '64', '91', '95', '125', '139', '166', '175', '200'] 

使用re.sub()：

>>> re.sub(r"[A-Z;,.]"," ",strs).split() 
['21', '48', '64', '91', '95', '125', '139', '166', '175', '200'] 

幫助（re.findall）：

Help on function findall in module re: 

findall(pattern, string, flags=0) 
Return a list of all non-overlapping matches in the string. 

If one or more groups are present in the pattern, return a 
list of groups; this will be a list of tuples if the pattern 
has more than one group. 

Empty matches are included in the result.