如何避免重複記錄併發請求在Laravel

Question

秒內請幫我找出問題。

有時（並不總是）我的下面的代碼在數據庫中插入兩條記錄（到用戶表和配置文件表中），但是我在插入之前檢查「mobile_no」已經存在，或者沒有做出唯一的手機號碼基於記錄。

static function postData($data) { 

    try { 
if (isset($data['number'])) { 
    //exist 
    $exist = Profile::where('mobile_no', '=', $data['number'])->get(); 
    //print_r($exist); 

    if (count($exist) > 0) {  
    $user = User::find($exist[0]['user_id']); 
    if (isset($data['last_name'])) { 
    $user->first_name = $data['first_name']; 
    } 
    if (isset($data['last_name'])) { 
    $user->last_name = $data['last_name']; 
    } 
    if (isset($data['email'])) { 
    $user->email = $data['email']; 
    } 
    $user->save(); 
    $proid = $exist[0]['user_id']; 
    $profile_result = Profile::find($proid); 


    if (isset($data['number'])) { 
    $profile_result->mobile_no = $data['number']; 
    } 
    if (isset($data['birthday'])) { 
    $profile_result->dob = $data['birthday']; 
    } 



    $profile_result->save(); 
    return $exist[0]['user_id']; 
    }else{ 

    $user = new User(); 
    if (isset($data['first_name'])) { 
    $user->first_name = $data['first_name']; 
    } 
    if (isset($data['last_name'])) { 
    $user->last_name = $data['last_name']; 
    } 


    $user->save(); 
    $id = $user->id; 
    $profile = new Profile(); 

    $profile->user_id = $id; 

    if (isset($data['mobile_number'])) { 
    $profile->mobile_no = $data['number']; 
    } 
    if (isset($data['birthday'])) { 
    $profile->dob = $data['birthday']; 
    } 
    $profile->save(); 

    $proid = $profile->user_id; 
    $profile_result = $profile::where('user_id', '=', $proid)->get(); 

    $user_result = $user::where('id', '=', $id)->get(); 

    $output = array(); 




    return (string) $id; 
    } 
    } 

    } catch (Exception $ex) 
    { 
    return $ex; 
    } 


    } 

Answer 1

對數據庫使用索引UNIQUE，它將爲您處理。只要記住在嘗試插入重複密鑰時正確處理錯誤。