在eclipse中的Webservice

Question

通過SOAP方法我想從android/eclipse中使用web服務。但是消費web服務的方式是，我必須提供一個輸入，並且它應該從Web服務返回適當的值。如何實現它？

Web方法

public class FahrenheitToCelsius { 
public double FahrenheitToCelsius(double Fahrenheit) 
{ 
    return ((Fahrenheit - 32) * 5)/9; 
} 
} 

的.java類

public class Demo_webserviceActivity extends Activity 
{ 
    /** Called when the activity is first created. */ 

     private static String NAMESPACE = "http://tempuri.org/"; 
     private static String METHOD_NAME = "FahrenheitToCelsius"; 
     private static String SOAP_ACTION = "http://tempuri.org/FahrenheitToCelsius"; 
     private static String URL = "http://www.w3schools.com/webservices/tempconvert.asmx?WSDL"; 

     Button btnFar; 
     EditText txtFar,txtCel; 

    @Override 
    public void onCreate(Bundle savedInstanceState) 
    { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.main); 

     btnFar = (Button)findViewById(R.id.btnFar); 

     txtFar = (EditText)findViewById(R.id.txtFar); 
     txtCel = (EditText)findViewById(R.id.txtCel); 

     btnFar.setOnClickListener(new View.OnClickListener() 
     { 

     public void onClick(View v) 
     { 
     //Initialize soap request + add parameters 
     SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);  

     //Use this to add parameters 
     request.addProperty("Fahrenheit",txtFar.getText().toString()); 

     //Declare the version of the SOAP request 
     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 

     envelope.setOutputSoapObject(request); 
     envelope.dotNet = true; 

     try 
     { 
      HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); 

      //this is the actual part that will call the webservice 
      androidHttpTransport.call(SOAP_ACTION, envelope); 

      // Get the SoapResult from the envelope body. 
      SoapObject result = (SoapObject)envelope.bodyIn; 

      if(result != null) 
      { 
       //Get the first property and change the label text 
       txtCel.setText(result.getProperty(0).toString()); 
      } 
      else 
      { 
       Toast.makeText(getApplicationContext(), "No Response",Toast.LENGTH_LONG).show(); 
      } 
     } 
     catch (Exception e) 
     { 
      e.printStackTrace(); 
      } 
     } 
     }); 
    } 
} 

Answer 1

從您的網址WSDL和嘗試

私人靜態字符串URL = 「HTTP？ //www.w3schools.com/webservices/ tempconvert.asmx「;