計算多種貨幣格式元素的總和

Question

我想創建一個基於一系列貨幣格式化數字的小計，但我正在努力將數字轉換回整數，以便可以添加它們。這是我曾嘗試：

$(function() { 
 
    var totals = $('.price'); 
 

 
    var sum = 0; 
 
    for (var i = 0; i < totals.length; i++) { 
 
    //strip out dollar signs and commas 
 
    $(totals[i].text()).replace(/[^\d.]/g, ''); 
 

 
    //convert string to integer 
 
    var ct = parseFloat($(totals[i].text())); 
 
    sum += ct; 
 
    } 
 

 
    console.log(sum); 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<div class="price">$195,000.20</div> 
 
<div class="price">$21,404.00</div> 
 
<div class="price">$7,000.00</div> 
 
<div class="price">$450.00</div>

Answer 1

replace()不會修改傳遞的字符串（它不能在這裏無論如何，因爲它是一個函數的結果）。它只是返回的修改值。

保存的replace()的結果，和根據是：

$(function() { 
 
    var totals = $('.price'); 
 

 
    var sum = 0; 
 
    for (var i = 0; i < totals.length; i++) { 
 
    //strip out dollar signs and commas 
 
    var v = $(totals[i]).text().replace(/[^\d.]/g, ''); 
 

 
    //convert string to integer 
 
    var ct = parseFloat(v); 
 
    sum += ct; 
 
    } 
 

 
    console.log(sum); 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<div class="price">$195,000.20</div> 
 
<div class="price">$21,404.00</div> 
 
<div class="price">$7,000.00</div> 
 
<div class="price">$450.00</div>

另外：注意錯字 - 你想$(totals[i]).text()，不$(totals[i].text())