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對於我正在開發的wordpress網站,我正在製作一個動態菜單,用戶可以使用管理菜單進行製作。陷入這只是我的問題最少。修改PHP集合
代碼我使用返回這些陣列:
Array
(
[0] => WP_Post Object
(
[ID] => 35
[post_author] => 1
[post_date] => 2013-05-19 15:46:22
[post_date_gmt] => 2013-05-19 15:46:22
[post_content] =>
[post_title] =>
[post_excerpt] =>
[post_status] => publish
[comment_status] => open
[ping_status] => open
[post_password] =>
[post_name] => 35
[to_ping] =>
[pinged] =>
[post_modified] => 2013-05-19 16:07:09
[post_modified_gmt] => 2013-05-19 16:07:09
[post_content_filtered] =>
[post_parent] => 0
[guid] => http://adapt.local/?p=35
[menu_order] => 1
[post_type] => nav_menu_item
[post_mime_type] =>
[comment_count] => 0
[filter] => raw
[db_id] => 35
[menu_item_parent] => 0
[object_id] => 32
[object] => training
[type] => post_type
[type_label] => Training
[url] => http://adapt.local/training/alcohol/
[title] => Alcohol
[target] =>
[attr_title] =>
[description] =>
[classes] => Array
(
[0] =>
)
[xfn] =>
)
[1] => WP_Post Object
(
[ID] => 36
[post_author] => 1
[post_date] => 2013-05-19 16:07:09
[post_date_gmt] => 2013-05-19 16:07:09
[post_content] =>
[post_title] =>
[post_excerpt] =>
[post_status] => publish
[comment_status] => open
[ping_status] => open
[post_password] =>
[post_name] => 36
[to_ping] =>
[pinged] =>
[post_modified] => 2013-05-19 16:07:09
[post_modified_gmt] => 2013-05-19 16:07:09
[post_content_filtered] =>
[post_parent] => 0
[guid] => http://adapt.local/?p=36
[menu_order] => 2
[post_type] => nav_menu_item
[post_mime_type] =>
[comment_count] => 0
[filter] => raw
[db_id] => 36
[menu_item_parent] => 35
[object_id] => 32
[object] => training
[type] => post_type
[type_label] => Training
[url] => http://adapt.local/training/alcohol/
[title] => Alcohol
[target] =>
[attr_title] =>
[description] =>
[classes] => Array
(
[0] =>
)
[xfn] =>
)
)
爲了解釋:如果menu_item_parent = 0,這意味着它是頂節點,並且如果menu_item_parent> 0,這意味着它是一個'子節點」。
我想這個可怕的數組轉換到更有用的東西,最好是這樣的
Array
(
[35] => Array
(
name => "Topnode"
url => "http://topnodeurl"
items => Array
(
name => "Subnode"
url => "http://subnodeurl"
)
)
)
心想:嘿,這可能不是那麼難。但是,顯然,這似乎並沒有工作:
foreach($menuitems as $menuitem) {
if(!$menuitem->menu_item_parent) {
$items[$menuitem->ID] = array("name" => $menuitem->title,"items" => array());
#print_r($items);
}
else {
$parent = $items[$menuitem->menu_item_parent]['items'];
$parent = array("name" => $menuitem->title, "url" => $menuitem->url);
}
}
任何想法?
如何將這項工作?由於遞歸函數沒有返回任何東西,我不相信$ items ['childs']會做些什麼? –
抱歉,我的壞話忘了返回菜單 – MKroeders
完美!這似乎是做這項工作。我現在不應該擔心所有'額外數據'。這只是做一切。 –