子和額外的參數

Question

我嘗試使用下面的代碼：

args = 'LD_LIBRARY_PATH=/opt/java/jre/lib/i386/:/opt/java/jre/lib/amd64/ exec /opt/java/jre/bin/java -Xincgc -Xmx1G -jar craftbukkit-0.0.1-SNAPSHOT.jar'.split() 
p = subprocess.Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE) 

不過，我收到的結果是：

Traceback (most recent call last): 
File "launch.py", line 29, in <module> 
p = subprocess.Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE) 
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__ errread, errwrite) 
File "/usr/lib/python2.7/subprocess.py", line 1228, in _execute_child raise child_exception 
OSError: [Errno 2] No such file or directory 

沒有LD_LIBRARY_PATH的一部分，它工作正常。但是，我需要它。感謝您的幫助。

Answer 1

下面是避免使用shell的方法：

from subprocess import Popen 
from os import environ 

env = dict(os.environ) 
env['LD_LIBRARY_PATH'] = '/opt/java/jre/lib/i386/:/opt/java/jre/lib/amd64/' 
args = ['/opt/java/jre/bin/java', '-Xincgc', '-Xmx1G', '-jar', 'craftbukkit-0.0.1-SNAPSHOT.jar'] 
p = Popen(args, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE, env=env) 

Answer 2

嘗試增加shell = True到Popen電話：

p = subprocess.Popen(args, shell=True, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE) 

你使用設置LD_LIBRARY_PATH的語法是shell語法，因此有必要通過shell執行命令。