我有同樣的問題..它幫助我,我指定我的類的相同字段名稱作爲XML文件中的標記名稱(該文件來自外部系統)。
例如:
我的XML文件:
<Response>
<ESList>
<Item>
<ID>1</ID>
<Name>Some name 1</Name>
<Code>Some code</Code>
<Url>Some Url</Url>
<RegionList>
<Item>
<ID>2</ID>
<Name>Some name 2</Name>
</Item>
</RegionList>
</Item>
</ESList>
</Response>
我的迴應類:
@XmlRootElement(name="Response")
@XmlAccessorType(XmlAccessType.FIELD)
public class Response {
@XmlElement
private ESList[] ESList = new ESList[1]; // as the tag name in the xml file..
// getter and setter here
}
我ESList類:
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name="ESList")
public class ESList {
@XmlElement
private Item[] Item = new Item[1]; // as the tag name in the xml file..
// getters and setters here
}
我的項目類:
@XmlRootElement(name="Item")
@XmlAccessorType(XmlAccessType.FIELD)
public class Item {
@XmlElement
private String ID; // as the tag name in the xml file..
@XmlElement
private String Name; // and so on...
@XmlElement
private String Code;
@XmlElement
private String Url;
@XmlElement
private RegionList[] RegionList = new RegionList[1];
// getters and setters here
}
我RegionList類:
@XmlRootElement(name="RegionList")
@XmlAccessorType(XmlAccessType.FIELD)
public class RegionList {
Item[] Item = new Item[1];
// getters and setters here
}
我DemoUnmarshalling類:
public class DemoUnmarshalling {
public static void main(String[] args) {
try {
File file = new File("...");
JAXBContext jaxbContext = JAXBContext.newInstance(Response.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
jaxbUnmarshaller.setEventHandler(
new ValidationEventHandler() {
public boolean handleEvent(ValidationEvent event) {
throw new RuntimeException(event.getMessage(),
event.getLinkedException());
}
}
);
Response response = (Response) jaxbUnmarshaller.unmarshal(file);
ESList[] esList = response.getESList();
Item[] item = esList[0].getItem();
RegionList[] regionLists = item[0].getRegionList();
Item[] regionListItem = regionLists[0].getItem();
System.out.println(item[0].getID());
System.out.println(item[0].getName());
System.out.println(item[0].getCode());
System.out.println(item[0].getUrl());
System.out.println(regionListItem[0].getID());
System.out.println(regionListItem[0].getName());
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
它提供:
1
Some name 1
Some code
Some Url
2
Some name 2
對於那些來到這裏從搜索,我只是要評論由產生的來源,這是更容易,如果你是混合兩種不同生成的源目錄使用不正確的'ObjectFactory',這是可以引起的。 – bbarker 2017-05-06 01:28:06