你將如何從main調用數據並將其傳遞給函數？ （C++）

Question

所以我有麻煩從主函數（一個數組與你輸入的變量）調用數據，並不知道如何將它傳遞給一個float getTotal函數。這裏是我的代碼：

#include <iostream> 
#include <iomanip> 

using namespace std; 

float getTotal(float [], int) 
    { 
    double total = 0; 
    for (int i=1; i<ARRAYSIZE; i++) 
     { 
      total += inputs[i]; 
     } 
    cout << "The total rainfall for the year is " << total << "inches." << endl; 
    return total; 
    } 

float getAverage(float [], int) 
    { 
    //code goes here 
    } 

int main() 
    { 
    const int ARRAYSIZE = 13; 
    int inputs[ARRAYSIZE], i=1; 
    do 
     { 
      cout << "Enter the rainfall (in inches) for month #" << i << ": "; 
      cin >> inputs[i]; 
      if (inputs[i] < 0) 
       { 
        cout << "Please enter a non-negative number for rainfall in month " << i << " :"; 
        cin >> inputs[i]; 
       } 
      i++; 
     } 
    while (i < 13); 

    float getTotal(float inputs[], int ARRAYSIZE); 
    float getAverage(float inputs[], int ARRAYSIZE); 
    } 

所以我想打電話從主陣列數據和計算的getTotal段總。我嘗試了各種方法，其中沒有一個能夠工作。

Answer 1

float getTotal(float inputs[], int ARRAYSIZE) 
    { 
    double total = 0; 
    for (int i=1; i<ARRAYSIZE; i++) 
     { 
      total += inputs[i]; 
     } 
    cout << "The total rainfall for the year is " << total << "inches." << endl; 
    return total; 
    } 

float getAverage(float inputs[], int ARRAYSIZE) 
    { 
    //code goes here 
    } 

int main() 
    { 
    const int ARRAYSIZE = 13; 
    int inputs[ARRAYSIZE], i=1; 
    do 
     { 
      cout << "Enter the rainfall (in inches) for month #" << i << ": "; 
      cin >> inputs[i]; 
      if (inputs[i] < 0) 
       { 
        cout << "Please enter a non-negative number for rainfall in month " << i << " :"; 
        cin >> inputs[i]; 
       } 
      i++; 
     } 
    while (i < 13); 

    float fTotal = getTotal(inputs, ARRAYSIZE); 
    float fAverage = getAverage(inputs, ARRAYSIZE); 
    } 

Answer 2

更換你的函數聲明：

float getTotal(float [], int) 
float getAverage(float [], int) 

這個

float getTotal(int* inputs, int ARRAYSIZE) 
float getAverage(int* inputs, int ARRAYSIZE) 

而此行的main（）函數中：

float getTotal(float inputs[], int ARRAYSIZE); 
float getAverage(float inputs[], int ARRAYSIZE); 

這個

float getTotal(inputs, ARRAYSIZE); 
float getAverage(inputs, ARRAYSIZE); 

Answer 3

我們的源代碼有太多的錯誤。例如「int inputs [ARRAYSIZE]」。您的數組 是int數據類型，但是您將此數組作爲float數據類型傳遞。有一個編譯器
錯誤。其次，你應該在主函數之外聲明函數和它的數據類型，但是你在主函數 裏面做的
float getTotal（float inputs []，int ARRAYSIZE）; 還有另一個編譯器錯誤。在調用函數時，您不需要指定參數的數據類型 。所以我寫了一個可能的代碼，希望它能幫助你。

#include <iostream> 
#include <iomanip> 

using namespace std; 

float getTotal(int *inputs, int ARRAYSIZE) 
    { 
    double total = 0; 
    for (int i=1; i<=ARRAYSIZE; i++) 
     { 
     total += inputs[i]; 
     } 
     cout << "The total rainfall for the year is " << total << "inches." << endl; 
    return total; 

}

float getAverage(int *inputs, int ARRAYSIZE) 
    { 
    //code goes here 

    return 1.4; 
    } 

int main() 
    { 
    const int ARRAYSIZE = 3; 
    int inputs[ARRAYSIZE], i=1; 
    do 
     { 
     cout << "Enter the rainfall (in inches) for month #" << i << ": "; 
     cin >> inputs[i]; 
     if (inputs[i] < 0) 
      { 
      cout << "Please enter a non-negative number for rainfall in month " << i  
       << " :"; 
       cin >> inputs[i]; 
      } 
     i++; 
    } 
while (i <= 3); 

    getTotal(inputs, ARRAYSIZE); 
    getAverage(inputs, ARRAYSIZE); 

return 0; 

}

 While calling function, the return value you can store in variable but data type of 

     variable should be the same of return type of the function 

     e.g float a = getTotal(inputs, ARRAYSIZE); 
    float b = getAverage(inputs, ARRAYSIZE); 
     or you can directly call this function in cout output command statement.like 

COUT < < getTotal（輸入，ARRAYSIZE）;

Answer 4

喜@ user2901840的代碼稍加修改允許它運行良好：

#include <iostream> 
#include <iomanip> 

using namespace std; 

float getTotal(float floatarray[], int size) 
{ 
    float total = 0.0f; 
    for (int i=0; i<size; i++) 
    { 
     total += floatarray[i]; 
    } 
    return total; 
} 

float getAverage(float floatarray[], int size) 
    { 
     return (getTotal(floatarray, size))/size; 
    } 

int main() 
    { 
     int ARRAYSIZE = 12, i=0; 
     float inputs[ARRAYSIZE]; 
     do 
     { 
      cout << "Enter the rainfall (in inches) for month #" << i << ": "; 
      cin >> inputs[i]; 
      if (inputs[i] < 0.0) 
       { 
        cout << "Please enter a non-negative number for rainfall in month " << i << " :"; 
        cin >> inputs[i]; 
       } 
      i++; 
     } 
     while (i < ARRAYSIZE); 
     cout << "\n\nThe total rainfall for the year is " << getTotal(inputs, ARRAYSIZE) << " inches." << endl; 
     cout << "The average rainfall per month during the year was: " << getAverage(inputs, ARRAYSIZE) << " inches."<< endl; 
    } 

您需要正確的預定義類，並在需要調用進行修改。爲了說明我有的代碼： - 重新編號以匹配常見C++約定（對12個值運行0到11）的i值 - 重新使用函數以最小化代碼 - 將數組重新聲明爲浮點數組最初有它作爲整數數組）

希望這有助於:)

讓我知道，如果你需要更多的細節和解釋，我可以在更多的信息填寫。