修改字符串後保留第一個位置的大寫字母

Question

我正在編寫一個程序，將輸入的字詞更改爲拉丁語。我的代碼可以正常工作，除了大寫之外，所有內容都應該如此。如果輸入的單詞是以資本出租開始的，我想做第一個位置，即單詞[0]。我嘗試了很多方法，但似乎無法弄清楚。任何幫助，將不勝感激。

word=input("Enter the word: ") 

word=word.lower() 

if word.isalpha(): 
    if word[0:len(word)] not in ' ': 
    if word[0] in 'aeiou': 
     word=word + 'yay' 
     print(word) 
    elif word[0:1] in 'qu': 
     word=word[2:]+word[0]+word[1] +'ay' 
     print(word) 
    elif word[0] not in 'aeiou': 
     while(word[0] not in 'aeiou'): 
     word=word[1:]+word[0:1] 
     word=word+'ay' 
     print(word) 

    else: 
    print("Invalid Word") 
else: 
    print("Invalid Word") 

Answer 1

試試這個：

#!/usr/bin/python 

capitalize = False 

word=input("Enter the word: ") 

if word[0] in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ': 
    capitalize = True 

word = word.lower() 

if word.isalpha(): 
    if word[0:len(word)] not in ' ': 
    if word[0] in 'aeiou': 
     word=word + 'yay' 
    elif word[0:1] in 'qu': 
     word=word[2:]+word[0]+word[1] +'ay' 
    elif word[0] not in 'aeiou': 
     while(word[0] not in 'aeiou'): 
     word=word[1:]+word[0:1] 
     word=word+'ay' 
    else: 
    print("Invalid Word") 
else: 
    print("Invalid Word") 

if capitalize is True: 
    word = word.title() 

print(word) 

Answer 2

你可以試試這個方法：

word=input("Enter the word: ") 

if word[0].isupper() and word.isalpha(): 
    word=word.lower() 
    if word[0:len(word)] not in ' ': 
     if word[0] in 'aeiou': 
     word=word + 'yay' 
     print(word[0].upper() + word[1:]) 
     elif word[0:1] in 'qu': 
     word=word[2:]+word[0]+word[1] +'ay' 
     print(word[0].upper() + word[1:]) 
     elif word[0] not in 'aeiou': 
     while(word[0] not in 'aeiou'): 
      word=word[1:]+word[0:1] 
     word=word+'ay' 
     print(word[0].upper() + word[1:]) 
    else: 
     print("Invalid Word") 

elif word[0].islower() and word.isalpha(): 
    word=word.lower() 
    if word[0:len(word)] not in ' ': 
     if word[0] in 'aeiou': 
     word=word + 'yay' 
     print(word) 
     elif word[0:1] in 'qu': 
     word=word[2:]+word[0]+word[1] +'ay' 
     print(word) 
     elif word[0] not in 'aeiou': 
     while(word[0] not in 'aeiou'): 
      word=word[1:]+word[0:1] 
     word=word+'ay' 
     print(word) 
    else: 
     print("Invalid Word") 

else: 
    print("Invalid Word") 

爲了更好地理解這裏編譯above代碼。