將視圖中的列表傳遞給表單

Question

我在我的views.py中有一個視圖，在我的forms.py中有一個表單。 我需要將我的視圖的列表[]傳遞給我的表單的MultipleChoiceField。

這是我的代碼，我當然想念的東西...

非常感謝

views.py

def view_favorite(request): 
     media = settings.MEDIA 
     game_logo = settings.GAME_LOGO 
     if request.user.is_authenticated(): 
      if request.method == 'POST' : 
       return render(request, 'favorite.html', locals()) 
      else: 
       favs = FavoriteGames.objects.filter(user_id=request.user.id).values_list('game_id', flat=True) 
       list = [] 
       for fav in favs: 
        game = Games.objects.get(id=fav) 
        list.append((game.id, game.guid, game.title, game.logo, "checked"),) 
        nogame = Games.objects.filter(~Q(id__in=favs)).values_list('id', 'guid', 'title', 'logo') 
       form = GamesEditorForm(list) 

forms.py

class GamesEditorForm(forms.Form): 
    def __init__(self, list, *args, **kwargs): 
     super(GamesEditorForm, self).__init__(*args, **kwargs) 

    favorite_games = forms.MultipleChoiceField(
     required=True, 
     initial=True, 
     widget=forms.CheckboxSelectMultiple(), 
     choices=list, 
     ) 

Answer 1

你可以傳給你數據直接作爲功能參數

views.py

from .forms import my_func 

def some_func(request): 
    my_list = [1,2,3] 
    my_func(request, my_list) 

forms.py

def my_func(request, my_list): 
    #Do something with my_list 

Answer 2

你可以做的是覆蓋默認的init方法爲表單，並創建窗體時處理所有的邏輯：

class YourOwnForm(forms.Form): 
    a_field = forms.IntegerField(
     label="field", 
     widget=forms.HiddenInput()) 

    def __init__(self, your_custom_list=None, *args, **kwargs): 
     """ 
     Intantiation service. 
     This method extends the default instantiation service. 
     """ 
     super(CustomizationForm, self).__init__(*args, **kwargs) 
     if your_custom_list: 
      do stuff... 
     else: 
      error... 

你會這樣稱呼它：

my_form = YourOwnForm(data, your_custom_list=[5,8,9])