鐵血陣列通過聲明數組

Question

我搜索，但沒有找到在C＃

我已經宣佈和分配陣列的解決方案：

string[] arr1 = {"a","b","c","d","e","f"}; 
string[] arr2 = {"1","2","3","4","5","6"}; 
string[] arr3 = {"s","t","a","c","k","o"}; 
string[] arr4 = {"v","e","r","f","l","w"}; 

我要讓那些陣列交錯數組，但沒有成功。

string[,] port = new string[] 
{ 
    new string[] arr1[], 
    new string[] arr2[], 
    new string[] arr3[], 
    new string[] arr4[], 
}; 

我犯的錯誤在哪裏？

我的計劃會產生隨機int s到來自鋸齒狀排列調用值

Random random = new Random(); 
int x = random.Next(0,5); 
int y = random.Next(0,3); 
Console.WriteLine(port[y,x]); 

Answer 1

有兩種錯誤：

1. 你不聲明鋸齒狀陣列，但多維一。由於你的「內部」數組已經定義好了，所以你需要一個陣列這就是所謂的「鋸齒狀」陣列。
2. 你不需要new string[]在聲明中，你已經聲明內陣列

所以這應該工作：

string[][] port = new string[][] 
{ 
    arr1, arr2, arr3, arr4 
}; 

或數組初始化更短：

string[][] port = { arr1, arr2, arr3, arr4 }; 

---

要訪問此數組，請使用：

Console.WriteLine(port[y][x]); 

Answer 2

試試這個：

string[] arr1 = { "a", "b", "c", "d", "e", "f" }; 
string[] arr2 = { "1", "2", "3", "4", "5", "6" }; 
string[] arr3 = { "s", "t", "a", "c", "k", "o" }; 
string[] arr4 = { "v", "e", "r", "f", "l", "w" }; 

string[][] port = new string[4][]; 
port[0] = arr1; 
port[1] = arr2; 
port[2] = arr3; 
port[3] = arr4; 

或者乾脆：

string[][] port = new string[][] { arr1, arr2, arr3, arr4 }; 

用法：

string test = port[1][5];