zend路由正則表達式問題

Question

我想在ini文件中創建一個匹配以下URL的路由，但我一直沒有成功。

/add-announce.html 
/add-announce-books-53.html 

我的路線是這樣的：

routes.add_announcement.type = "Zend_Controller_Router_Route_Regex" 
routes.add_announcement.route = "/add-announce(-[a-zA-Z_]+)?(-[\d]+)?.html" 
routes.add_announcement.defaults.module = announcement 
routes.add_announcement.defaults.controller = frontend 
routes.add_announcement.defaults.action = add 
routes.announcements.defaults.catName = null 
routes.announcements.defaults.catId = null 
routes.add_announcement.map.catName = 1 
routes.add_announcement.map.catId = 2 

Answer 1

也許是因爲你的比賽有 ' - ' 開頭？你可以嘗試：

routes.add_announcement.route = "add-announce(?:-([a-zA-Z_]+))?(?:-([\d]+))?.html" 

編輯：我剛剛找到了錯誤，您設置映射值錯誤：

routes.add_announcement.map.catName = 1 
routes.add_announcement.map.catId = 2 

相反，你必須做這樣的：

routes.add_announcement.map.1 = "catName" 
routes.add_announcement.map.2 = "catId" 

而且routes.announcements.defaults.catName不應該routes.add_announcement.defaults.catName？