PHP/MySQL - while循環只顯示最近輸入的記錄

我試圖讓while循環顯示從表中選擇的所有記錄，並迭代封裝在< div>中的結果。我的查詢正在工作，並且正在顯示一些內容......但只有最新的記錄。我無法弄清楚爲什麼會這樣，而且我對PHP很陌生，所以任何幫助都會很棒。PHP/MySQL - while循環只顯示最近輸入的記錄

代碼：

<?php 
//Connect to database and select table 
$conn = mysql_connect("", "", "") or die(mysql_error()); 
mysql_select_db("substest", $conn) or die(mysql_error()); 
//Issue query 
$get_features = "SELECT ID, Title, DateReceived, Synopsis FROM features ORDER BY ID"; 
$r_get_features = mysql_query($get_features) or die(mysql_error); 

if(mysql_num_rows($r_get_features) < 1) { 
    $display_block = "<div class=\"inner\"><h2>Nothing to display</h2></div>"; 
} 
else { 
    while($feat_array = mysql_fetch_array($r_get_features)) { 
    $feat_id = $feat_array["ID"]; 
    $feat_title = stripslashes($feat_array["Title"]); 
    $feat_dater = stripslashes($feat_array["DateReceived"]); 
    $feat_synopsis = stripslashes($feat_array["Synopsis"]); 

    $display_block = "<div class=\"inner\">"; 
    $display_block .= "<h2>".$feat_title."</h2>"; 
    $display_block .= "<label for \"id\">ID:</label>"; 
    $display_block .= "<span class=\"formresult\" id=\"id\">".$feat_id."</span><br />"; 
    $display_block .= "<label for=\"title\">Title:</label>"; 
    $display_block .= "<span class=\"formresult\" id=\"title\">".$feat_title."</span><br />"; 
    $display_block .= "<label for=\"datereceived\">Date Received:</label>"; 
    $display_block .= "<span class=\"formresult\" id=\"datereceived\">".$feat_dater."</span><br />"; 
    $display_block .= "<label for=\"synopsis\">Synopsis:</label>"; 
    $display_block .= "<span class=\"formresult\" id=\"synopsis\">".$feat_synopsis."</span><br />"; 
    $display_block .= "</div>"; 
} 
} 
?> 
<html> 
<head> 
<title>Galway Film Fleadh - View Submitted Feature Films</title> 
<link href="css/submissions.css" rel="stylesheet" type="text/css" /> 
</head> 

<body> 
<div id="wrapper"> 
    <div class="inner"> 
     <h1>Galway Film Fleadh - View Submitted Films</h1> 
    </div> 
    <?php 
     print $display_block; 
    ?> 
</div>   
</body> 
</html>

來源

2013-03-28 Shane Malone

你覆蓋$display_block每個循環迭代：

$display_block = "<div class=\"inner\">";

循環之前將其定義，然後將上面的行更改爲：

$display_block .= "<div class=\"inner\">";

來源

2013-03-28 16:04:43

我知道這將是一個小的東西....謝謝！ –

試着改變你的一段時間：

while($feat_array = mysql_fetch_array($r_get_features, MYSQLI_ASSOC)) { 
...

來源

2013-03-28 16:04:23 Andrew

通過

$display_block .= "<div class=\"inner\">";

來源

2013-03-28 16:04:57 TheEwook

$display_block = "<div class=\"inner\">";

替換該行

$display_block = "<div class=\"inner\">";

是while循環裏面，所以每次迭代一次得到一個新值，不保持前一。

來源

2013-03-28 16:05:24

因爲

$display_block = "<div class=\"inner\">";

是循環在內部循環，同時在div被instanstiated每次迭代後左右....

您需要保留舊的值，所以你必須來連接它。 .. 取代它

$display_block .= "<div class=\"inner\">";

來源

2013-03-28 16:10:35 alwaysLearn

PHP/MySQL - while循環只顯示最近輸入的記錄

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