PHP從數據庫中檢索圖像錯誤

-2

我正試圖從數據庫中調用圖像。我已經建立了圖像正確到達數據庫，但是當我拉下圖像時，我得到了使其成爲可能的Blob文本。我如何下拉圖像才能顯示圖像？PHP從數據庫中檢索圖像錯誤

<?php 
    //libs 
    include 'library/config.php'; 
    include 'library/opendb.php'; 
    //query 
    $query = "SELECT * FROM `upload` WHERE `postID`=".$elem["postID"].";"; 
    $result = mysqli_query($conn, $query); 
    if (mysqli_num_rows($result) > 0) { // if results exist 
     while ($row = mysqli_fetch_assoc($result)) { // assign db cont to variable 
      $name = $row["name"]; 
      $size = $row["size"]; 
      $type = $row["type"]; 
      $content = $row["content"]; 
      // header info 
      header("Content-length: $size"); 
      header("Content-type: $type"); 
      header("Content-Disposition: attachment; filename=$name"); 
      //display image 
      echo "img", $content; 
     } 
     include 'library/closedb.php'; 
    ?>

來源

2017-02-02 Nate langner

你已經在mysql中BLOB數據類型？ –

[如何從MySQL數據庫檢索圖像並顯示在html標籤中]可能的重複（http://stackoverflow.com/questions/7793009/how-to-retrieve-images-from-mysql-database-and-display- in-an-html-tag） –

Possibel重複http://stackoverflow.com/questions/20556773/php-display-image-blob-from-mysql –

使用

$content = base64_encode($_row['content']);

顯示JPEG圖像。

http://php.net/manual/en/function.base64-encode.php

來源

2017-02-02 13:32:30

$code_base64 = $row['content']; 
$code_base64 = str_replace('data:image/jpeg;base64,','',$code_base64); 
$code_binary = base64_decode($code_base64); 
$image= imagecreatefromstring($code_binary); 
header('Content-Type: image/jpeg'); 
imagejpeg($image); 
imagedestroy($image);

來源

2017-02-02 13:45:09 akuthedeveloper

PHP從數據庫中檢索圖像錯誤

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