SQLite的說：「沒有這樣的列：的rowid」使用子查詢時

Question

這裏的工作正常的查詢：

SELECT rowid as msg_rowid, a, b, c FROM messages m1 

這裏還有另外一個，也是罰款：

SELECT rowid as match_rowid FROM messages m2 WHERE x LIKE '%abc%' 

但如果我把在一起如下，SQLite的抱怨：

SELECT rowid as msg_rowid, a, b, c FROM messages m1 
JOIN 
    (SELECT rowid as match_rowid FROM messages m2 WHERE x LIKE '%abc%') 
ON 
    msg_rowid >= match_rowid - 10 AND msg_rowid <= match_rowid + 5 

給予什麼樣子了誤導性的錯誤消息：No such column: rowid。

我該如何解決這個問題？

查詢運行正常，如果我使用一個messages.timestamp場，而不是ROWID的：

SELECT timestamp as msg_ts, a, b, c FROM messages m1 
JOIN 
    (SELECT timestamp as match_ts FROM messages m2 WHERE x LIKE '%abc%') 
ON 
    msg_ts >= match_ts - 10 AND msg_ts <= match_ts + 5 

這是一個錯誤，或者對使用rowid一個由設計限制？

Answer 1

由GuZzie在評論中回答。出於某種原因，SQLite要求我明確說明外部rowid：

SELECT m1.rowid as msg_rowid, a, b, c FROM messages m1 
     ^^ HERE 
JOIN 
    (SELECT rowid as match_rowid FROM messages m2 WHERE x LIKE '%abc%') 
ON 
    msg_rowid >= match_rowid - 10 AND msg_rowid <= match_rowid + 5