Django all（）得到了一個意想不到的關鍵字參數'user'

Question

我正在開發一個簡單的應用程序。我的應用程序允許用戶創建一個帳戶並添加電路板。

我試圖檢索用戶創建並顯示在模板上的所有板，而不會出現此錯誤。

all() got an unexpected keyword argument 'user' 

Traceback: 
File "C:\Python26\Lib\site-packages\django\core\handlers\base.py" in get_response 
111.       response = callback(request, *callback_args, **callback_kwargs) 
File "C:\o\mysite\pet\views.py" in Display 
69.  board = Board.objects.all(user=request.user) 

我的models.py

from django.db import models 
from django.db.models.signals import post_save 
from django.contrib.auth.models import User 

class Person(models.Model): 
    user = models.ForeignKey(User) 
    name = models.CharField(max_length=100) 
    image = models.FileField(upload_to="images/",blank=True,null=True) 


    def __unicode__(self): 
     return self.name 

class Board(models.Model): 
    user = models.ForeignKey(User) 
    name = models.CharField(max_length=100) 
    def __unicode__(self): 
     return self.name 

我views.py的部分（問題是在這裏）

def Display(request): 
    if not request.user.is_authenticated(): 
     return HttpResponseRedirect(reverse('pet.views.LoginRequest')) 
    board = Board.objects.all(user=request.user) 
    return render(request,'edit.html',{'board':board}) 

我edit.html

{% if board %} 
<ul>   
    <li>Name: {{ board.name }}</li> 

</ul> 
{% endif %} 

Answer 1

all（）是全部。如果您想查詢基於價值使用的過濾器（）

def Display(request): 
    if not request.user.is_authenticated(): 
     return HttpResponseRedirect(reverse('pet.views.LoginRequest')) 
    board = Board.objects.filter(user=request.user) 
    return render(request,'edit.html',{'board':board}) 

{% if board %} 
<ul> 
    {% for b in board %}   
    <li>Name: {{ b.name }}</li> 
    {% endfor %} 
</ul> 
{% endif %} 

Answer 2

要獲得所有與在user是request.user，你應該使用filter方法。所以相反：

board = Board.objects.filter(user=request.user) 

希望這能解決它！