計數與特定字符開頭的文件

Question

我有以下文件::

FirstName, FamilyName, Address, PhoneNo 

文件根據姓氏排序，我怎麼能算姓氏的數量開始以特定字符？

輸出應該是這樣的：

A: 2 
B: 1 
... 

？

Answer 1

使用awk：

awk '{print substr($2, 1, 1)}' file| 
    uniq -c| 
    awk '{print $2 ": " $1}' 

OK，沒AWK。這裏有sed：

sed s'/[^,]*, \(.\).*/\1/' file| 
    uniq -c| 
    sed 's/.*\([0-9]\)\+ \([a-zA-Z]\)\+/\2: \1/' 

好的，沒有sed。下面是使用Python：

import csv 
r = csv.reader(open(file_name, 'r')) 
d = {} 
for i in r: 
    d[i[1][1]] = d.get(i[1][1], 0) + 1 
for (k, v) in d.items(): 
    print "%s: %s" % (k, v) 

Answer 2

while read -r f l r; do echo "$l"; done < inputfile | cut -c 1 | sort | uniq -c 

Answer 3

「硬辦法」 的要求—沒有用AWK或sed中的，正是對。如果您不確定這些命令中的任何一個是什麼意思，那麼您一定要查看每個命令的man page。

INTERMED=`mktemp`  # Creates a temporary file 
COUNTS_L=`mktemp`  # A second... 
COUNTS_R=`mktemp`  # A third... 

cut -d , -f 2 |   # Extracts the FamilyName field only 

tr -d '\t ' |   # Deletes spaces/tabs 

cut -c 1 |   # Keeps only the first character 
       # on each line 

tr '[:lower:]' '[:upper:]' | # Capitalizes all letters 

sort |    # Sorts the list 

uniq -c > $INTERMED  # Counts how many of each letter 
       # there are 

cut -c1-7 $INTERMED |  # Cuts out the LHS of the temp file 
tr -d ' ' > $COUNTS_R  # Must delete the padding spaces though 


cut -c9- $INTERMED > $COUNTS_L # Cut out the RHS of the temp file 

# Combines the two halves into the final output in reverse order 
paste -d ' ' /dev/null $COUNTS_R | paste -d ':' $COUNTS_L - 

rm $INTERMED $COUNTS_L $COUNTS_R # Cleans up the temp files 

Answer 4

就在殼牌

#! /bin/bash 

##### Count occurance of familyname initial 

#FirstName, FamilyName, Address, PhoneNo 
exec <<EOF 
Isusara, Ali,  Someplace, 022-222 
Rat,  Fink,  Some Hole, 111-5555 
Louis, Frayser, whaterver, 123-1144 
Janet, Hayes, whoever St,  111-5555 
Mary, Holt,  Henrico VA, 222-9999 
Phillis, Hughs, Some Town, 711-5525 
Howard, Kingsley, ahahaha, 222-2222 
EOF 



while read first family rest 
do 
    init=${family:0:1} 
    [ -n "$oinit" -a $init != "$oinit" ] && { 
     echo $oinit : $count 
     count=0 
    } 
    oinit=$init 
    let count++ 
done 

echo $oinit : $count 

運行

frayser@gentoo ~/doc/Answers/src/SH/names $ sh names.sh 
A : 1 
F : 2 
H : 3 
K : 1 
frayser@gentoo ~/doc/Answers/src/SH/names $ 

從文件中讀取，刪除文件在這裏，然後運行：

chmod +x names.sh 
./names.sh <file 

Answer 5

AWK單行：

awk ' 
    {count[substr($2,1,1)]++} 
    END {for (init in count) print init ": " count[init]} 
' filename 

Answer 6

打印多少字開始與每個字母：

對於i在{A..Z};做echo -n「$ i：」; find path/to/folder -type f -exec sed「s// \ n/g」{} \; | grep^$ i | wc -c | awk'{print $ 0}';完成