每個在每個邏輯

Question

我嘗試做以下的XSLT 1.0：

複製所有的是爲輸出，其中的條件是弗拉姆元素的任何弗拉姆的屬性（@name和@type和@ref的）值與任何XFram元素相匹配，那麼它應該用XFram/text（）更新Fram/text（）。在複製剩餘的XFram元素之後（所有這些都符合上述條件）並將它們轉換爲Fram標記。

注意：第三個Fram元素的所有屬性都與第三個Xfram元素相匹配，因此在第三個Fram元素中添加了文本。其餘的XFarm元素轉換爲Fram元素並添加到最後的Fram元素之後。你也會注意到Fram的訂單沒有改變。

Input.xml中

<Doc>AL 
<Frams> 
<Fram type="x" name="Fram1" ref="ref1">This is Fram One</Fram> 
<Fram type="y" name="Fram2" ref="ref2">This is Fram Two</Fram> 
<Fram type="z" name="Fram3" ref="ref3">This is Fram Three</Fram> 
<Fram type="a" name="Fram4" ref="ref3">This is Fram Four</Fram> 
<Fram type="b" name="Fram5" ref="ref3">This is Fram Five</Fram> 
</Frams> 
<XFram> 
<XFram type="e" name="XFram1" ref="Xref1">This is XFram One</Fram> 
<XFram type="f" name="XFram2" ref="Xref2">This is XFram Two</Fram> 
<XFram type="z" name="XFram3" ref="Xref3">This is XFram Three</Fram> 
<XFram type="e" name="XFram1" ref="Xref1">This is XFram Four</Fram> 
<XFram> 
<Doc> 

輸出應該是：

<Doc> 
<Frams> 
<Fram type="x" name="Fram1" ref="ref1">This is Fram One</Fram> 
<Fram type="y" name="Fram2" ref="ref2">This is Fram Two</Fram> 
<Fram type="z" name="Fram3" ref="ref3">This is XFram Three</Fram> 
<Fram type="a" name="Fram4" ref="ref3">This is Fram Four</Fram> 
<Fram type="b" name="Fram5" ref="ref3">This is Fram Five</Fram> 
<XFram type="e" name="XFram1" ref="Xref1">This is XFram One</Fram> 
<XFram type="f" name="XFram2" ref="Xref2">This is XFram Two</Fram> 
<XFram type="e" name="XFram1" ref="Xref1">This is XFram Four</Fram> 
</Frams> 
<Doc> 

我做這樣的事情，但沒能想到的邏輯：

<xsl:template match="/"> 
    <xsl:for-each select="XFram"> 
     <xsl:variable name="type"> 
      <xsl:value-of select="type"/> 
     </xsl:variable> 
     <xsl:variable name="name"> 
      <xsl:value-of select="name"/> 
     </xsl:variable> 
     <xsl:variable name="ref"> 
      <xsl:value-of select="ref"/> 
     </xsl:variable> 
     <xsl:for-each select="//Fram"> 
      <xsl:choose> 
       <xsl:when test="(type = $type) and (name = $name) and (ref = $ref)"> </xsl:when> 
      </xsl:choose> 
     </xsl:for-each>   
    </xsl:for-each> 
</xsl:template> 

Answer 1

這種轉變：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:template match="node()|@*" name="identity"> 
    <xsl:copy> 
    <xsl:apply-templates select="node()|@*"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="Fram[last()]"> 
    <xsl:call-template name="identity"/> 

    <xsl:apply-templates 
     select="../../XFram/*"/> 
</xsl:template> 

<xsl:template match="XFram/XFram"> 
    <xsl:if test= 
    "not(/*/Frams/* 
      [@type = current()/@type 
      and 
       concat('X',@name) = current()/@name 
      and 
       concat('X',@ref) = current()/@ref 
      ] 
     )"> 
    <xsl:copy-of select="."/> 
    </xsl:if> 
</xsl:template> 
<xsl:template match="XFram"/> 
</xsl:stylesheet> 

當所提供的XML文檔施加（具有校正嚴重malformedness !!!）：

<Doc> 
    <Frams> 
     <Fram type="x" name="Fram1" ref="ref1">This is Fram One</Fram> 
     <Fram type="y" name="Fram2" ref="ref2">This is Fram Two</Fram> 
     <Fram type="z" name="Fram3" ref="ref3">This is Fram Three</Fram> 
     <Fram type="a" name="Fram4" ref="ref3">This is Fram Four</Fram> 
     <Fram type="b" name="Fram5" ref="ref3">This is Fram Five</Fram> 
    </Frams> 
    <XFram> 
     <XFram type="e" name="XFram1" ref="Xref1">This is XFram One</XFram> 
     <XFram type="f" name="XFram2" ref="Xref2">This is XFram Two</XFram> 
     <XFram type="z" name="XFram3" ref="Xref3">This is XFram Three</XFram> 
     <XFram type="e" name="XFram1" ref="Xref1">This is XFram Four</XFram></XFram> 
</Doc> 

產生想要的，正確的結果：

<Doc> 
    <Frams> 
     <Fram type="x" name="Fram1" ref="ref1">This is Fram One</Fram> 
     <Fram type="y" name="Fram2" ref="ref2">This is Fram Two</Fram> 
     <Fram type="z" name="Fram3" ref="ref3">This is Fram Three</Fram> 
     <Fram type="a" name="Fram4" ref="ref3">This is Fram Four</Fram> 
     <Fram type="b" name="Fram5" ref="ref3">This is Fram Five</Fram> 
     <XFram type="e" name="XFram1" ref="Xref1">This is XFram One</XFram> 
     <XFram type="f" name="XFram2" ref="Xref2">This is XFram Two</XFram> 
     <XFram type="e" name="XFram1" ref="Xref1">This is XFram Four</XFram> 
    </Frams> 
</Doc>