JSON - 如何合併嵌套對象內部數組在PHP

Question

您好我希望把JSON嵌套的對象與此格式：

[{"lat":-6.92015,"lon":107.67024,"value":0.1},{"lat":-6.88283,"lon":107.60149,"value":0.1},..] 

這個JSON數組：

{"max": 30, "data": [...]} 

，並會導致在此格式：

{"max": 30, "data": [{"lat":-6.92015,"lon":107.67024,"value":0.1},...]} 

我當前的代碼：

$data[] = array(lat=>(float)$row["geo_lat"], lon=>(float)$row["geo_long"], value=>1); 
$post_data = json_encode(array('max' => 30, 'data' => $data)); 
echo $post_data; 

我該怎麼做？由於

Answer 1

檢查：

$array = json_decode('[{"lat":-6.92015,"lon":107.67024,"value":0.1},{"lat":-6.88283,"lon":107.60149,"value":0.1}]'); 

print_r($array); 

$final_array = array('max'=>30,'data'=>$array); 
print_r($final_array); 

$output = json_encode($final_array); 
print $output; 

代碼在行動：eval.in