我有一個網址「http://184.82.158.234/~store/rest/system/connect.json」和發佈此網址與mozilla插件稱爲海報返回數據的形式json 我想要的是從Android發佈此網址以將該json數據轉換爲android視圖。從Android發佈URL來檢索數據
任何幫助,高度讚賞 感謝
我有一個網址「http://184.82.158.234/~store/rest/system/connect.json」和發佈此網址與mozilla插件稱爲海報返回數據的形式json 我想要的是從Android發佈此網址以將該json數據轉換爲android視圖。從Android發佈URL來檢索數據
任何幫助,高度讚賞 感謝
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://184.82.158.234/~store/rest/system/connect.json");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
響應變量將包含您的JSON數據。
查看下面的代碼:試試這可能會幫助你。
ArrayList nameValuePairs1 = new ArrayList();
nameValuePairs1.add(new BasicNameValuePair("user_id", ""));
nameValuePairs1.add(new BasicNameValuePair("product_id", ""));
nameValuePairs1.add(new BasicNameValuePair("product_review",""+text));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(URL);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs1));
HttpResponse responce = httpclient.execute(httppost);
HttpEntity entity = responce.getEntity();
is = entity.getContent();
BufferedReader bufr = new BufferedReader(new InputStreamReader(is1,"iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
sb.append(bufr.readLine() + "\n");
String line = "0";
while ((line = bufr.readLine()) != null)
{
sb.append(line + "\n");
}
is1.close();
result = sb.toString();
結果是一個json字符串。解析該json並在任何控件中顯示。我在文本視圖中顯示了這一點,見下文。
好吧,讓我試試 你可以告訴我這是什麼?代碼 nameValuePairs1.add(new BasicNameValuePair(「user_id」,「」)); nameValuePairs1.add(new BasicNameValuePair(「product_id」,「」)); nameValuePairs1.add(new BasicNameValuePair(「product_review」,「」+ text));'code' 因爲我得到的響應沒有任何參數 –
這是你必須發送的參數, www.xyz.com?name=dhaval&product_id=1&product_review=4。這是get方法,但如果你想使用post方法,那麼你必須傳遞數組中的數據,就像我在使用nameValuePairs1數組的答案中寫的一樣。 –
*** *** 05-14 17:35:50.541:E/AndroidRuntime(1216):java.lang.RuntimeException:無法啓動活動ComponentInfo {com.post/com.post.PostActivity}:android.os.NetworkOnMainThreadException * * 這是讓我的應用程序崩潰,我不知道如何解決它 幫助plzzz –
這裏是一個函數,也許你可以用來發佈一個字符串到一個URL。
public String doHttpPost(final String fullUrl, final String body) {
final URL url = new URL(fullUrl);
final HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
// set the request mode as POST
urlConnection.setRequestMethod("POST");
urlConnection.setUseCaches(false);
urlConnection.setDoOutput(true);
urlConnection.setRequestProperty("Accept-charset", "utf-8");
urlConnection.setRequestProperty("Content-type", "application/x-www-form-urlencoded");
final DataOutputStream request = new DataOutputStream(urlConnection.getOutputStream());
// write the body.
request.writeBytes(body);
// flush output buffer
request.flush();
request.close();
// construct a read using input stream and charset.
final InputStreamReader isr = new InputStreamReader(urlConnection.getInputStream(), CHARSET_UTF8);
final BufferedReader in = new BufferedReader(isr);
String inputLine;
final StringBuilder stringBuilder = new StringBuilder();
while ((inputLine = in.readLine()) != null) {
stringBuilder.append(inputLine).append("\n");
}
in.close();
isr.close();
urlConnection.disconnect();
return stringBuilder.toString();
}
的兄弟,我已經嘗試過烏拉圭回合的解決方案不工作的感謝答覆 –
和U可以PLZ告訴我Ÿ我不得不這樣做 nameValuePairs.add(新BasicNameValuePair(「ID」,「12345」)); 因爲我的網址不採取任何參數它只是返回數據沒有任何參數 –
你不能解析json嗎?你可以擴大你的問題多一點 –