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有沒有什麼方法可以編程識別附近的GSM塔的位置,我們可以在地圖上顯示它們?獲取GSM塔的位置
有沒有什麼方法可以編程識別附近的GSM塔的位置,我們可以在地圖上顯示它們?獲取GSM塔的位置
您可以使用谷歌地圖API查詢Lat Long網基於BST ID(塔)
實例C#:
using System;
using System.IO;
using System.Net;
//---Based on code written by "Neil Young" ([email protected])
//---Source: http://maps.alphadex.de/datafiles/fct0e1b11782832f02.cs
namespace GoogleMaps
{
class GMM
{
static byte[] PostData(int MCC, int MNC, int LAC, int CID,
bool shortCID)
{
/* The shortCID parameter follows heuristic experiences:
* Sometimes UMTS CIDs are build up from the original GSM CID (lower 4 hex digits)
* and the RNC-ID left shifted into the upper 4 digits.
*/
byte[] pd = new byte[] {
0x00, 0x0e,
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,
0x00, 0x00,
0x00, 0x00,
0x00, 0x00,
0x1b,
0x00, 0x00, 0x00, 0x00, // Offset 0x11
0x00, 0x00, 0x00, 0x00, // Offset 0x15
0x00, 0x00, 0x00, 0x00, // Offset 0x19
0x00, 0x00,
0x00, 0x00, 0x00, 0x00, // Offset 0x1f
0x00, 0x00, 0x00, 0x00, // Offset 0x23
0x00, 0x00, 0x00, 0x00, // Offset 0x27
0x00, 0x00, 0x00, 0x00, // Offset 0x2b
0xff, 0xff, 0xff, 0xff,
0x00, 0x00, 0x00, 0x00
};
bool isUMTSCell = ((Int64)CID > 65535);
if (isUMTSCell)
Console.WriteLine("UMTS CID. {0}", shortCID ?
"Using short CID to resolve." : "");
else
Console.WriteLine("GSM CID given.");
if (shortCID)
CID &= 0xFFFF; /* Attempt to resolve the cell using the
GSM CID part */
if ((Int64)CID > 65536) /* GSM: 4 hex digits, UTMS: 6 hex
digits */
pd[0x1c] = 5;
else
pd[0x1c] = 3;
pd[0x11] = (byte)((MNC >> 24) & 0xFF);
pd[0x12] = (byte)((MNC >> 16) & 0xFF);
pd[0x13] = (byte)((MNC >> 8) & 0xFF);
pd[0x14] = (byte)((MNC >> 0) & 0xFF);
pd[0x15] = (byte)((MCC >> 24) & 0xFF);
pd[0x16] = (byte)((MCC >> 16) & 0xFF);
pd[0x17] = (byte)((MCC >> 8) & 0xFF);
pd[0x18] = (byte)((MCC >> 0) & 0xFF);
pd[0x27] = (byte)((MNC >> 24) & 0xFF);
pd[0x28] = (byte)((MNC >> 16) & 0xFF);
pd[0x29] = (byte)((MNC >> 8) & 0xFF);
pd[0x2a] = (byte)((MNC >> 0) & 0xFF);
pd[0x2b] = (byte)((MCC >> 24) & 0xFF);
pd[0x2c] = (byte)((MCC >> 16) & 0xFF);
pd[0x2d] = (byte)((MCC >> 8) & 0xFF);
pd[0x2e] = (byte)((MCC >> 0) & 0xFF);
pd[0x1f] = (byte)((CID >> 24) & 0xFF);
pd[0x20] = (byte)((CID >> 16) & 0xFF);
pd[0x21] = (byte)((CID >> 8) & 0xFF);
pd[0x22] = (byte)((CID >> 0) & 0xFF);
pd[0x23] = (byte)((LAC >> 24) & 0xFF);
pd[0x24] = (byte)((LAC >> 16) & 0xFF);
pd[0x25] = (byte)((LAC >> 8) & 0xFF);
pd[0x26] = (byte)((LAC >> 0) & 0xFF);
return pd;
}
static public string GetLatLng(string[] args)
{
if (args.Length < 4)
{
return string.Empty;
}
string shortCID = ""; /* Default, no change at all */
if (args.Length == 5)
shortCID = args[4].ToLower();
try
{
String url = "http://www.google.com/glm/mmap";
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(
new Uri(url));
req.Method = "POST";
int MCC = Convert.ToInt32(args[0]);
int MNC = Convert.ToInt32(args[1]);
int LAC = Convert.ToInt32(args[2]);
int CID = Convert.ToInt32(args[3]);
byte[] pd = PostData(MCC, MNC, LAC, CID,
shortCID == "shortcid");
req.ContentLength = pd.Length;
req.ContentType = "application/binary";
Stream outputStream = req.GetRequestStream();
outputStream.Write(pd, 0, pd.Length);
outputStream.Close();
HttpWebResponse res = (HttpWebResponse)req.GetResponse();
byte[] ps = new byte[res.ContentLength];
int totalBytesRead = 0;
while (totalBytesRead < ps.Length)
{
totalBytesRead += res.GetResponseStream().Read(
ps, totalBytesRead, ps.Length - totalBytesRead);
}
if (res.StatusCode == HttpStatusCode.OK)
{
short opcode1 = (short)(ps[0] << 8 | ps[1]);
byte opcode2 = ps[2];
int ret_code = (int)((ps[3] << 24) | (ps[4] << 16) |
(ps[5] << 8) | (ps[6]));
if (ret_code == 0)
{
double lat = ((double)((ps[7] << 24) | (ps[8] << 16)
| (ps[9] << 8) | (ps[10])))/1000000;
double lon = ((double)((ps[11] << 24) | (ps[12] <<
16) | (ps[13] << 8) | (ps[14])))/
1000000;
return lat + "|" + lon;
}
else
return string.Empty;
}
else
return string.Empty;
}
catch (Exception)
{
return string.Empty;
}
}
}
}
感謝你的快速的答案,但我不明白這一點,你能幫我理解這一點嗎,有關這方面的任何閱讀鏈接? – 2011-03-31 15:26:02
此代碼將BTS ID發送到谷歌地圖以獲取GSM塔的位置。相關文章:http://brainwashinc.wordpress.com/2009/06/26/cell-phone-my-location-google-mobile-maps/ – 2011-03-31 15:29:09
非常感謝!它真的幫助...! :) – 2011-04-01 16:01:05