顯示網頁瀏覽器請求

我試圖表現出404頁未找到無法從服務器顯示網頁瀏覽器請求

import java.io.BufferedReader; 
import java.io.DataOutputStream; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.net.ServerSocket; 
import java.net.Socket; 

public class ex1 { 

/** 
* @param args 
*/ 
public static void main(String[] args) { 
    // TODO Auto-generated method stub 
    final int BUFFER_SIZE=1000; 
    char[] buffer=new char[BUFFER_SIZE]; 
    ServerSocket serverSocket = null; 
    try { 
     serverSocket = new ServerSocket(16000); 
    } catch (IOException e) { 
     System.out.println("Could not listen on port: 16000"); 
     System.exit(-1); 
    } 
    while (true) { 
     Socket clientSocket = null; 
     try { 
      System.out.println("Waiting for Connection"); 
      clientSocket = serverSocket.accept(); 
      System.out.println("Connection Accepted"); 
      DataOutputStream output =new DataOutputStream(clientSocket.getOutputStream()); 
      output.writeBytes("HTTP/1.1 404 Not Found \r\n"); 
      output.writeBytes("Content-Type: text/html \r\n\r\n"); 


      output.flush(); 
     } catch (IOException e) { 
      System.out.println("Failed to accept connection"); 
      System.exit(-1); 
     } 
     try { 
      BufferedReader in = 
      new BufferedReader(new InputStreamReader(clientSocket.getInputStream())); 
      in.read(buffer); 
      System.out.println(buffer); 
      in.close(); 
      clientSocket.close(); 
      System.out.println("Connection terminated"); 
      serverSocket.close(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
      System.out.println("Problem in communicating with the client"); } 
    } 
} 
}

發現的問題是，當我鍵入localhost：16000到我的瀏覽器（谷歌瀏覽器）我得到「糟糕！這個鏈接似乎被打破了。「不是頁面404

輸出爲：

Waiting for Connection 
Connection Accepted 
java.net.SocketException: Connection reset 
Problem in communicating with the client 
Waiting for Connection 
Connection Accepted 
GET/HTTP/1.1 
Host: localhost:16000 
Connection: keep-alive 
Cache-Control: max-age=0 
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 
User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/537.22 (KHTML, like Gecko) Chrome/25.0.1364.172 Safari/537.22 
Accept-Encoding: gzip,deflate,sdch 
Accept-Language: en-US,en;q=0.8 
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3 


Connection terminated 
Waiting for Connection 
Failed to accept connection 
    at java.net.SocketInputStream.read(SocketInputStream.java:189) 
    at java.net.SocketInputStream.read(SocketInputStream.java:121) 
    at sun.nio.cs.StreamDecoder.readBytes(StreamDecoder.java:283) 
    at sun.nio.cs.StreamDecoder.implRead(StreamDecoder.java:325) 
    at sun.nio.cs.StreamDecoder.read(StreamDecoder.java:177) 
    at java.io.InputStreamReader.read(InputStreamReader.java:184) 
    at java.io.BufferedReader.fill(BufferedReader.java:154) 
    at java.io.BufferedReader.read1(BufferedReader.java:205) 
    at java.io.BufferedReader.read(BufferedReader.java:279) 
    at java.io.Reader.read(Reader.java:140) 
    at ex1_Getting_your_hands_dirty.ex1.main(ex1.java:55)

如何解決這一問題？

來源

2013-03-20 user1673892

我不認爲'HTTP/1.x 404 Not Found'是一個有效的狀態行。也許用'0'或'1'代替'1.x'中的'x'？ – 2013-03-20 01:28:44

另外，我認爲一個HTTP響應應該至少有一個標頭，通常是「內容長度」 - 並且正文中的一些內容是一個好主意。 – 2013-03-20 01:29:47

@RichardJPLeGuen JP LEGUEN ON MY SO！！？ – 2013-03-20 01:34:11

它在我看來像你的HTTP響應無效。

HTTP/1.x 404 Not Found

您應該：

更改1.x到正確的版本號，比如1.0
添加響應主體
添加至少一個頭 - 也許Content-Length和Content-Type

更多內容像...

HTTP/1.1 404 Not Found 
Content-Length: 9 
Content-Type: text/plain 

Not Found

來源

2013-03-20 01:32:28

我得到W白頁與我寫的 – user1673892 2013-03-20 01:59:50

我改變了這部分是 output.writeBytes（「HTTP/1.1 404 Not Found \ r \ n」）; output.writeBytes（「Content-Type：text/html \ r \ n \ r \ n」）; output.writeBytes（「Content-Length：9」）; output.writeBytes（「Content-Type：text/plain」）; \t output.writeBytes（「Not Found」）; 與同花順，但我得到這個 Content-Length：9Content-Type：text/plainNot Found – user1673892 2013-03-20 02:00:59

顯示網頁瀏覽器請求

回答

相關問題