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假設我有一個共同執行調用這樣的兩個類:如何用mockito存根異步調用?
public class blah {
@Autowired
private ExecutorServiceUtil executorServiceUtil;
@Autowired
private RestTemplate restClient;
public SomeReturnType getDepositTransactions(HttpHeaders httpHeaders) {
ExecutorService executor = executorServiceUtil.createExecuter();
try {
DepositTransactionsAsyncResponse asyncResponse = getPersonalCollectionAsyncResponse(httpHeaders, executor);
// do some processing
// return appropriate return type
}finally {
executorServiceUtil.shutDownExecutor(executor);
}
}
Future<ResponseEntity<PersonalCollectionResponse>> getPersonalCollectionAsyncResponse(HttpHeaders httpHeaders, ExecutorService executor) {
PersonalCollectionRequest personalCollectionRequest = getpersonalCollectionRequest(); // getPersonalCollectionRequest populates the request appropriately
return executor.submit(() -> restClient.exchange(personalCollectionRequest, httpHeaders, PersonalCollectionResponse.class));
}
}
public class ExecutorServiceUtil {
private static Logger log = LoggerFactory.getLogger(ExecutorServiceUtil.class);
public ExecutorService createExecuter() {
return Executors.newCachedThreadPool();
}
public void shutDownExecutor(ExecutorService executor) {
try {
executor.shutdown();
executor.awaitTermination(5, TimeUnit.SECONDS);
}
catch (InterruptedException e) {
log.error("Tasks were interrupted");
}
finally {
if (!executor.isTerminated()) {
log.error("Cancel non-finished tasks");
}
executor.shutdownNow();
}
}
}
如何使用到的Mockito的存根的響應,並立即返回呢?
我已經試過以下,但我innovcation.args()返回[空]
PowerMockito.when(executor.submit(Matchers.<Callable<ResponseEntity<OrxPendingPostedTrxCollectionResponseV3>>> any())).thenAnswer(new Answer<FutureTask<ResponseEntity<OrxPendingPostedTrxCollectionResponseV3>>>() {
@Override
public FutureTask<ResponseEntity<OrxPendingPostedTrxCollectionResponseV3>> answer(InvocationOnMock invocation) throws Throwable {
Object [] args = invocation.getArguments();
Callable<ResponseEntity<OrxPendingPostedTrxCollectionResponseV3>> callable = (Callable<ResponseEntity<OrxPendingPostedTrxCollectionResponseV3>>) args[0];
callable.call();
return null;
}
});
有了@ GhostCat的建議,我可以使呼叫同步返回並允許我刪除答覆邏輯。 – Norbert