2014-02-10 52 views
-3

我有一個情況我需要訪問的表頭複選框 我與alterrnate爲accesing的DOM元素

document.getElementsByClassName("table_th_label_div")[0]; 

這樣做,但一些舊的瀏覽器不支持.getElementsByClassName我需要爲同一

替代appproach好心幫 預先感謝

+0

IE8支持'querySelectorAll'(有點) – elclanrs

+0

您能否告訴我下調投票的理由? –

+1

我想,因爲你的問題沒有顯示你的部分研究。有幾個dups http://stackoverflow.com/questions/9568969/getelementsbyclassname-ie8-object-doesnt-support-this-property-or-method,http://stackoverflow.com/questions/13261506/getelementsbyclassname-in -ie8,http://stackoverflow.com/questions/10484467/ie-8-object-doesnt-support-property-or-method-getelementsbyclassname – elclanrs

回答

2

solution可能會有幫助。這是在純javascript中實現的getElementsByClassName函數,可在IE中使用。

/* 
    Developed by Robert Nyman, http://www.robertnyman.com 
    Code/licensing: http://code.google.com/p/getelementsbyclassname/ 
*/ 
var getElementsByClassName = function (className, tag, elm){ 
    if (document.getElementsByClassName) { 
     getElementsByClassName = function (className, tag, elm) { 
      elm = elm || document; 
      var elements = elm.getElementsByClassName(className), 
       nodeName = (tag)? new RegExp("\\b" + tag + "\\b", "i") : null, 
       returnElements = [], 
       current; 
      for(var i=0, il=elements.length; i<il; i+=1){ 
       current = elements[i]; 
       if(!nodeName || nodeName.test(current.nodeName)) { 
        returnElements.push(current); 
       } 
      } 
      return returnElements; 
     }; 
    } 
    else if (document.evaluate) { 
     getElementsByClassName = function (className, tag, elm) { 
      tag = tag || "*"; 
      elm = elm || document; 
      var classes = className.split(" "), 
       classesToCheck = "", 
       xhtmlNamespace = "http://www.w3.org/1999/xhtml", 
       namespaceResolver = (document.documentElement.namespaceURI === xhtmlNamespace)? xhtmlNamespace : null, 
       returnElements = [], 
       elements, 
       node; 
      for(var j=0, jl=classes.length; j<jl; j+=1){ 
       classesToCheck += "[contains(concat(' ', @class, ' '), ' " + classes[j] + " ')]"; 
      } 
      try { 
       elements = document.evaluate(".//" + tag + classesToCheck, elm, namespaceResolver, 0, null); 
      } 
      catch (e) { 
       elements = document.evaluate(".//" + tag + classesToCheck, elm, null, 0, null); 
      } 
      while ((node = elements.iterateNext())) { 
       returnElements.push(node); 
      } 
      return returnElements; 
     }; 
    } 
    else { 
     getElementsByClassName = function (className, tag, elm) { 
      tag = tag || "*"; 
      elm = elm || document; 
      var classes = className.split(" "), 
       classesToCheck = [], 
       elements = (tag === "*" && elm.all)? elm.all : elm.getElementsByTagName(tag), 
       current, 
       returnElements = [], 
       match; 
      for(var k=0, kl=classes.length; k<kl; k+=1){ 
       classesToCheck.push(new RegExp("(^|\\s)" + classes[k] + "(\\s|$)")); 
      } 
      for(var l=0, ll=elements.length; l<ll; l+=1){ 
       current = elements[l]; 
       match = false; 
       for(var m=0, ml=classesToCheck.length; m<ml; m+=1){ 
        match = classesToCheck[m].test(current.className); 
        if (!match) { 
         break; 
        } 
       } 
       if (match) { 
        returnElements.push(current); 
       } 
      } 
      return returnElements; 
     }; 
    } 
    return getElementsByClassName(className, tag, elm); 
}; 
+0

是的,我明白。但解決方案太長,不能直接回答。所以這就是爲什麼我給他的解決方案的鏈接。和它的工作。 – RealDeepak

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感謝Quantas。但是,如果用戶再次訪問此鏈接,他們將完全理解其工作原理。但無論如何,謝謝。 – RealDeepak

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當然,這就是爲什麼你有第一個鏈接。但是如果有一天這個人沒有更新他們的域名,那麼這個答案就沒用了,這就是爲什麼最好在答案中有主要觀點(在這種情況下是代碼)。 –