import java.util.Scanner;
public class InteractiveRectangle
{
public static void main(String[] args)
{
do
{
int length = readInteger ("For Length ");
System.out.println();
int width = readInteger ("For Width ");
printRectangleDetails(length,width);// existing code goes here
}
while (keepGoing());
System.out.println("Goodbye, friend");
}
/**
* returns the details of the rectangle
* @param height the height of the rectangle
* @param width the width of the rectangle
*/
public static void printRectangleDetails (int length, int width)
{
System.out.println ("This is the length of the rectangle " + length);
System.out.println ("This is the width of the rectangle " + width);
System.out.println (("This is the perimeter of the rectangle " + (length + width)));
System.out.println (("This is the area of the rectangle " + (length * width)));
}
/**
* Read in an integer and return its value
* @param the prompt to be shown to the user
*/
public static int readInteger(String prompt)
{
System.out.println (prompt);
Scanner scan = new Scanner(System.in);
System.out.println("Enter an integer");
while (!scan.hasNextInt()) // while non-integers are present
{
scan.next();
System.out.println ("Bad input. Enter an integer.");
}
int input = scan.nextInt();
return input;
}
/**
* Read a positive integer and return its value
* @param the prompt to be shown to the user
*/
public static int readPositiveInteger(String prompt)
{
System.out.println (prompt);
Scanner scan = new Scanner(System.in);
System.out.println("Enter an integer");
boolean positive = false;
while (scan.hasNextInt() && positive == false)
{
int input = scan.nextInt();
if (input > 0)
{
positive = true;
{
return input;
}
}
else
{
System.out.println ("Bad input enter an integer.");
positive = false;
scan.nextLine();
}
}
return 0;
}
/**
* Ask the user whether or not to spawn another rectangle
* and returns the result as a boolean
*/
public static boolean keepGoing()
{
Scanner scan = new Scanner(System.in);
boolean inputRead = false;
boolean result = false;
System.out.println ("Do you want to process another rectangle?");
scan.next();
String input = scan.next();
if (input == "y")
{
inputRead = true;
result = true;
}
else if (input == "n")
{
inputRead = true;
result = false;
}
else
{
System.out.println("Bad input please try again!");
scan.nextLine();
}
return result;
}
我想要的程序詢問用戶是否要產生另一個矩形,並繼續下去,直到用戶回答與「N」這個問題。 Atm運行程序時,矩形只產生一次,所以我認爲我的keepGoing方法存在問題。 任何幫助,將不勝感激, 謝謝!
謝謝,你所說的話是有道理的。但是,有一件事,當它詢問我是否想要產生另一個矩形時,我必須先輸入'y'然後輸入'y',然後才能運行,有什麼想法? –
是的,因爲你沒有在你的輸入中存儲'first scan.next()'。看到我的第二點。當用'scan.next()'讀取時,第一個包含'input',第二個'scan.next()'包含'newline'。 –
現在啊,工作得很好,非常感謝! –