的Java迭代器停止unexpectadely

我的代碼進行迭代是，的Java迭代器停止unexpectadely

Iterator<BrokerDeals> it = listBrokerDeals.iterator(); 
ArrayList<BrokerDeals> listBrokerDeals_new = new ArrayList<BrokerDeals>(); 
        while (it.hasNext()) 
        { 
         BrokerDeals deals = it.next(); 
         Log.i("TRACE==","deals.ok_id"+deals.getOkId()); 
         if(!(deals.getOkId().equalsIgnoreCase(null))) 
         { 
          Log.i("TRACE==","deals.ok_id inside cond"); 
          listBrokerDeals_new.add(deals); 
         } 

        } 

        Log.i("TRACE==","list broker deals" +listBrokerDeals_new);

我的日誌是

04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id6321r9hrr960780 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_idx9crv9119111a 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_iden27yx79ph6082241a 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_idkhvu42e929520 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_iduly4n9b9ne2071111a 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_idkcis9719n464179 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_id inside cond 
04-30 08:20:28.021 28449-28449/com.o.n I/TRACE==: deals.ok_idnull 
04-30 08:20:28.871 28449-29253/com.o.n I/qtaguid: Untagging socket 137

正如你可以在日誌中看到ITERATOR停止時deals.ok_id（）給出空和Log.i（「TRACE ==」，「list broker deals」+ listBrokerDeals_new）;這永遠不會被打印。

任何想法爲什麼程序停止沒有錯誤？

來源

2016-04-30 Ritzor

用於檢查getOkId（）是否爲空的代碼是錯誤的。

if(!(deals.getOkId().equalsIgnoreCase(null)))

它應該是：

if(!(deals.getOkId() == null))

因爲該方法需要一個非空字符串。正如在其JavaDoc中指出：

該方法返回true，如果參數不是null和琴絃是相等的，忽略大小寫;否則爲假。

來源

2016-04-30 03:15:32 CConard96

的Java迭代器停止unexpectadely

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